Woodworking Asked on February 13, 2021
I am working on a project that has three 2×12’s supporting a load of 12,000 lbs. similar, but not exactly, to how joists support a house.
The 2×12’s are supporting about 6,000 lbs. on each end.
The three 2×12’s are:
a) Each cut to 90in.
b) The load takes up 24in. from each end of the 2×12’s leaving 42in. of free space in between.
c) The three 2×12’s are spaced parallel to each other, with one 2×12 being 24in. in front of the other.
d) The 6,000lb. (On each side) load is laying on a thick wooden plank (on each end) that is perpendicular to the three 2×12’s. Similar to this picture (I don’t know if it will show up in the post) "J" is the joist but in this picture there are 4 joists.
e) The two thick wooden planks on each end of 2×12’s (mentioned in “d”) is securely fastened to the 1.5in. part of the 2×12’s, as well as having blocking and other bolted wooden members that leaves (as stated in “b”) 42 in. Of free space in between.
f) The three 2×12’s are only 12in. off the ground.
Everything is stable and strong without any issues except for one.
I need to lift this so that it is 14in. off the ground (lifting it 2 in. in total).
Removing the load; as well as dissembling is not an option.
This will have to be lifted with the three 2×12’s and everything above (including load) remaining intact.
My best option is to lift (with a hydraulic jack) the front most 2×12 to 14in. and then lift the back most 2×12 to 14in. -I’ve done this before with no problems.
The only problem, that I have now, is that directly under the 2×12 is things that I can not remove and is not strong enough jack it from.
The saddle of the jack is 2-3/4in. All wood is Kiln-Dried Douglas Fir #2 or better.
My plan is to grade 8 bolt a 4×4 cut to 7in. directly in the middle of the free space, mentioned in “b”; plus having the 4×4 cut to 7in. will provide more of a direct clamping force the will be directly in line of the upward force of the jack and the downward gravitational force of the joist when it is being jacked up.
This 4×4 will be bolted to the outward face of the 11.25in. part of the front most and back most 2×12’s.
Questions:
Do you think is strong enough to support the load plus force of the jack or do you think it will just rip the 4×4 off of the 2×12; while also destroying the face of the 2×12’s?
P.S. This project is a hoppy type of thing I am doing and it is not anything that "construction" related.
I would probably go with a 6x6 and notch out two of the faces, without doing any math. Takes the weight from the bolts and allows them to provide clamping pressure only. Hard to say for sure without knowing exactly what your doing.
Answered by rjuzzle on February 13, 2021
You've got hydraulic jacks - even cheap ones will lift 2", so lift height isn't critical, so don't try to put your 4x4 vertically - that could be wobbly as it moves during the lift, and it concentrates all the lift force at one point on your structure.
This will give you 6 tons of weight plus the weight of the structure itself spread across 4 jacks. Theoretically, each jack is only taking about 1.5 tons. If you get four 6-ton jacks (which you can pick up pretty cheaply at the store that goes to the Harbor to get their Freight, or any automotive store), you'll have more than enough jacking capacity.
If the jacks at full extension don't reach the height you need, support each jack on some 2x6(or greater)x12" cuts stacked (and nailed/screwed to prevent movement) until the compressed jacks just touch the bottom of the 4x4.
I used a system similar to this to hold up our porch roof (on a 6x6) when we tore out the porch & columns below it to rebuild them. Supported some 2x10 on scaffolding, put the 6x6 on top of that, worked the jacks under, lifted the roof, put 6x6 support posts under it, released the jacks, removed the scaffold. Worked a treat. Used jacks from the aforementioned store with no problem - for the few extra bucks, I got two 12-ton jacks - significant overkill, I'm sure, but they held with no worries.
Answered by FreeMan on February 13, 2021
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