Web Applications Asked by user251141 on January 5, 2022
I am constructing a small app to consolidate slide decks within Google Drive.
For the most part the app works great. However, when I append a slide deck it only adds the first slide.
currentPresentation.appendSlide(org1Slides.getSlides()[0]);
Obviously it only returns the first slide because of [0]. I have tried removing the [0] and .getSlides() [0] portions altogether, which results in an error. I cannot find a way in the documentation to list more than one slide. I have also tried using a variation of for loops to pull each slide, but my current code just gets ignored.
for (var i = 0; i < org1Slides.length; i++) {
currentPresentation.appendSlide(org1Slides.getSlides()[i]);
}
and
for (slide in org1Slides) {
currentPresentation.appendSlide(org1Slides.getSlides()[slide]);
}
I am sure I am missing something small, but can someone point me in the direction of appending each slide from a presentation.
The desired outcome is that the code appends the entire slide deck to the overall presentation. The number of slides in each presentation is variable, so I can’t simply list each slide to be appended separately.
Full Code:
function consolidateSlides() {
// use the 'Org Base' slides as the baseline
var presentationId = '{presentation id hidden}';
// set current month, rename to current slide deck
var months = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'];;
var date = new Date();
var currentMonth = months[date.getMonth()] + ' ' + date.getFullYear();
var copyTitle = 'Meeting ' + currentMonth;
var copyFile = {
title: copyTitle,
};
copyFile = Drive.Files.copy(copyFile, presentationId);
// prepare current slide deck for appending org slides
var currentPresentation = SlidesApp.openById(copyFile.id);
// append org1 slides
var org1Slides = SlidesApp.openById('{presentation id hidden}');
currentPresentation.appendSlide(org1Slides.getSlides()[0]);
// append org2 slides
var org2Slides = SlidesApp.openById('{presentation id hidden});
currentPresentation.appendSlide(org2Slides.getSlides()[0]);
// append org3 slides
var org3Slides = SlidesApp.openById('{presentation id hidden}');
currentPresentation.appendSlide(org3Slides.getSlides()[0]);
// append org4 slides
var org4Slides = SlidesApp.openById('{presentation id hidden}');
currentPresentation.appendSlide(org4Slides.getSlides()[0]);
// append org5 slides
var org5Slides = SlidesApp.openById('1{presentation id hidden}');
currentPresentation.appendSlide(org5Slides.getSlides()[0]);
// append org6 slides
var org6Slides = SlidesApp.openById('{presentation id hidden}');
currentPresentation.appendSlide(org6Slides.getSlides()[0]);
};
I solved it after a few more hours of digging through documentation.
The openById() function does not return a list of slides. Using getSlides() provides a list of slides through which the for loop can iterate.
So
// append org1 slides
var org1Slides = SlidesApp.openById('{presentation id hidden}');
currentPresentation.appendSlide(org1Slides.getSlides()[0]);
Turned in to:
// append org1 slides
var org1Slides = SlidesApp.openById('{presentation id hidden}');
var currentSlides = org1Slides.getSlides();
for (slide in currentSlides) {
currentPresentation.appendSlide(org1Slides.getSlides()[slide]);
}
Answered by user251141 on January 5, 2022
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