Unix & Linux Asked by dsl on December 8, 2021
How to write a shell script to rename the file in linux?
Ex:
234-2020-08-06-12-13-14-abc_up.csv
is renamed to
234-abc_up-2020-08-06-12-13-14.csv
You could try sed
for the filename transformation (the syntax implies GNU sed
):
Example:
echo "234-2020-08-06-12-13-14-abc_up.csv" | sed -E 's/(.*)-([[:digit:]]{4}(-[[:digit:]]{2}){5})-([^.]+).csv/1-4-2.csv/'
234-abc_up-2020-08-06-12-13-14.csv
This will look for
YYYY-MM-DD-hh-mm-ss
notation (i.e. 4 digits, and then 5 times "dash, followed by 2 digits"), stored in "capture group" 2, and thenIt will replace this pattern with "capture group 1", "capture group 4", "capture group 2", followed by .csv
, which should meet your requirements.
If your sed
doesn't understand POSIX character classes, replace [[:digit:]]
by [0-9]
.
So, a shell script might look like
#!/bin/bash
fname="$1"
newname="$(sed -E 's/(.*)-([[:digit:]]{4}(-[[:digit:]]{2}){5})-([^.]+).csv/1-4-2.csv/' <<< "$fname")"
mv "$fname" "$newname"
Make sure to test it first, by replacing the mv
line with
echo "Would now execute 'mv $fname $newname'"
If you are not using bash
, you will have to change the command-substitution to
newname="$(echo "$fname" | sed -E etc.)"
Answered by AdminBee on December 8, 2021
This shell script would do the job:
#!/bin/bash
old_filename=$1
IFS='-' read -r -a arr <<< $old_filename # read dash-separated substrings into the array 'arr'
tmpsub=${arr[7]%.csv.gz} # extract 7th substring, stripping out the file extension
for i in $(seq 6 -1 1) # shifts right the substrings
do # in the array by one
arr[$(($i+1))]=${arr[$i]} # position, starting by 1
done
arr[1]=$tmpsub # set the substring 1 to the value of the previous 7th substring
new_filename=$(printf -- "-%s" "${arr[@]}") # join the substrings into a dash separated string
new_filename=${new_filename:1}".csv.gz" # add the extension
mv $old_filename $new_filename # rename the file
If you name it, e.g., rename_csv.sh
, and make it executable with chmod
, you can call it with just the original filename as input as follows:
./rename_csv.sh 234-2020-08-06-12-13-14-abc_up.csv.gz
It does not show any output, but it renames the file as it should.
Answered by Giuseppe Clemente on December 8, 2021
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