How to call .bashrc function in script

~/.bashrc
----
example()
{
    echo "example function"
}

If I use this in a shell script

#!/bin/sh

example

I get command not found.

I have tried

#!/bin/sh

source ~/.bashrc
example

but it doesn’t work.

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1. Call a .bashrc function from a bash shell script
2. How do you call a function defined in .bashrc from the shell?