Unix & Linux Asked on December 6, 2021
I’m writing a command line script to ‘unpack’ folders with .svg
files from downloads. I’ve copied the required files to a specific directory and now I need to delete all the directories with .svg
files in them because they are full of other formats and licences, which I don’t need. How do I do this?
Using GNU find we employ find within find to first look at a dir starting from the lower levels and then check whether that dir comprises atleast one .svg file. We delete such dirs.
$ find . -depth ! -name . -type d
-exec sh -c '
N=$#
for d do
test "x$(find "$d/." -maxdepth 1 -type f -name "*.svg" -print -quit)" != "x" &&
set -- "$@" "$d"
done
shift "$N"; rm -rf ${1+"$@"}
' find-sh {} +
Answered by Rakesh Sharma on December 6, 2021
GNUly, that could be:
LC_ALL=C find . -name '*.svg' -type f -printf '%h ' |
LC_ALL=C sort -zu |
xargs -r0 echo rm -rf
Where find
reports the dirname of all .svg
regular files, sort -zu
removes duplicates, and xargs rm
removes them.
That's not terribly efficient in that it keeps looking for .svg
files in children of a given directory even after .svg
file have been found in it.
Note that if the current directory contains .svg
files, rm
will refuse to delete it (as a safeguard on rm -rf .
to work around a misfeature in some shells where rm -rf .*
includes .
and ..
in the expansion of .*
).
You can work around that by replacing .
with "$PWD"
above.
Remove the echo
when you're satisfied it will do what you want.
With the bosh
shell, you could do it more efficiently with its builtin find
:
has_svg() {
find "$@" -maxdepth 1 -name '*.svg' -type f -call return 0 ;
return 1
}
find . -type d -call 'has_svg "$1"' {} ; -prune -exec echo rm -rf {} +
Answered by Stéphane Chazelas on December 6, 2021
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