TeX - LaTeX Asked by Violet on January 29, 2021
Consider this table I made. It’s actually much longer but for the purpose of illustration I’ve removed most rows.
begin{table}[h]
begin{tabular}{ccccccccc}
toprule
& & & & & multicolumn{4}{l}{Distance as determined by Algorithm} cmidrule(l){6-9}
multirow{-2}{*}{Leaves} & multirow{-2}{*}{Reticulations} & multirow{-2}{*}{$N$} & multirow{-2}{*}{$N'$} & multirow{-2}{*}{$d_{tail}(N,N')$} & 2.1 & 2.2 & 2.3 & 2.4 midrule
5 & 1 & 7 & 8 & 3 & 5 & 5 & 5 & 5
rowcolor[HTML]{EFEFEF}
5 & 1 & 8 & 9 & 2 & 2 & 2 & 2 & 2 bottomrule
end{tabular}
end{table}
I don’t know how to evenly distribute the cells underneath "distance as determined by Algorithm" in terms of width. I’ve tried using tabularx, but I couldn’t get it right.
I suggest you employ a tabularx
environment, set its width to textwidth
, and assign a centered version of the X
column type to 7 of the 9 columns. This setup will create an appearance of roughly equally wide columns.
documentclass{article}
usepackage[table]{xcolor}
usepackage{booktabs,ragged2e,amsmath,tabularx}
newcolumntype{C}{>{Centeringhspace{0pt}}X}
begin{document}
begin{table}
setlengthtabcolsep{2pt} % default: 6pt
begin{tabularx}{textwidth}{ cCCC c CCCC }
toprule
Leaves & Reticulations & $N$ & $N'$ & $d_{mathrm{tail}}(N,N')$ &
multicolumn{4}{>{hsize=dimexpr4hsize+6tabcolseprelax}C}{%
Distance as determined by algorithm}
cmidrule(l){6-9}
&&&&& 2.1 & 2.2 & 2.3 & 2.4
midrule
5 & 1 & 7 & 8 & 3 & 5 & 5 & 5 & 5
rowcolor[HTML]{EFEFEF}
5 & 1 & 8 & 9 & 2 & 2 & 2 & 2 & 2
bottomrule
end{tabularx}
end{table}
end{document}
Answered by Mico on January 29, 2021
Here are two solutions, one with the new w
column type, and the other with tabularx
, and the help of the makecell
package, which allows for line breaks in standard column types:
documentclass{article}
usepackage[table]{xcolor}
usepackage{booktabs}
usepackage{tabularx, multirow}
usepackage{makecell}
begin{document}
begin{table}[h]
centering
begin{tabular}{*{5}{c}*{4}{wc{6mm}}}
toprule
& & & & & multicolumn{4}{c}{makecell{Distance as determined by Algorithm}} cmidrule(l){6-9}
multirow{-2}{*}{Leaves} & multirow{-2}{*}{Reticulations} & multirow{-2}{*}{$N$} & multirow{-2}{*}{$N'$} & multirow{-2}{*}{$d_{mbox{tail}}(N,N')$} & 2.1 & 2.2 & 2.3 & 2.4 midrule
5 & 1 & 7 & 8 & 3 & 5 & 5 & 5 & 5
rowcolor[HTML]{EFEFEF}
5 & 1 & 8 & 9 & 2 & 2 & 2 & 2 & 2 bottomrule
end{tabular}
vskip1cm
begin{tabularx}{linewidth}{*{5}{c}*{4}{>{centeringarraybackslash}X}}
toprule
& & & & & multicolumn{4}{c}{makecell{Distance as determined by Algorithm}} cmidrule(l){6-9}
multirow{-2}{*}{Leaves} & multirow{-2}{*}{Reticulations} & multirow{-2}{*}{$N$} & multirow{-2}{*}{$N'$} & multirow{-2}{*}{$d_{mbox{tail}}(N,N')$} & 2.1 & 2.2 & 2.3 & 2.4 midrule
5 & 1 & 7 & 8 & 3 & 5 & 5 & 5 & 5
rowcolor[HTML]{EFEFEF}
5 & 1 & 8 & 9 & 2 & 2 & 2 & 2 & 2 bottomrule
end{tabularx}
end{table}
end{document}
Answered by Bernard on January 29, 2021
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