TeX - LaTeX Asked on August 13, 2021
Consider the following code:
documentclass[11pt]{article}
usepackage{amsthm,amsmath}
newtheorem{thm}{Theorem}
begin{document}
begin{thm}[Locality] For two fields $A(z)$ and $B(w)$, the followings are equivalent:
begin{itemize}
item $A(z)$ and $B(w)$ are local, i.e. $(z-w)^N[A(z), B(w)]=0$ for large $N$.
item $displaystyle [A(z), B(w)] = sum_{n=0}^{N-1} partial_w^{(j)} delta(z-w) gamma_n(w)$.
item begin{align*}
A(z)B(w) &= sum_{n=0}^{N-1} iota_{z,w} frac{1}{(z-w)^{n+1}} gamma_n(w) + :A(z)B(w):
(-1)^{|A||B|} B(w)A(z) &= sum_{n=0}^{N-1} iota_{w,z} frac{1}{(z-w)^{n+1}} gamma_n(w) + :A(z)B(w):.
end{align*}
end{itemize}
end{thm}
end{document}
I want to remove the blank line marked in red. So I tried to write down vspace{-baselineskip}
before the align*
environment. This gives the following weird result.
Just change begin{align*}
to quad$begin{aligned}[t]
and end{align*}
to end{aligned}$
.
documentclass[11pt]{article}
usepackage{amsthm,amsmath}
newtheorem{thm}{Theorem}
begin{document}
begin{thm}[Locality] For two fields $A(z)$ and $B(w)$, the followings are equivalent:
begin{itemize}
item $A(z)$ and $B(w)$ are local, i.e. $(z-w)^N[A(z), B(w)]=0$ for large $N$.
item $displaystyle [A(z), B(w)] = sum_{n=0}^{N-1} partial_w^{(j)} delta(z-w) gamma_n(w)$.
item quad$begin{aligned}[t]
A(z)B(w) &= sum_{n=0}^{N-1} iota_{z,w} frac{1}{(z-w)^{n+1}} gamma_n(w) +{} :A(z)B(w):
(-1)^{|A||B|} B(w)A(z) &= sum_{n=0}^{N-1} iota_{w,z} frac{1}{(z-w)^{n+1}} gamma_n(w) +{} :A(z)B(w):,.
end{aligned}$
end{itemize}
end{thm}
end{document}
Correct answer by Mico on August 13, 2021
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