TeX - LaTeX Asked on March 25, 2021
So I want to create a command setcol{A}{n}
which should produce {A}^{[n]}
when called like this I also want setcol{setcol{A}{n}}{m}
to produce {A}^{[n][m]}
rather than {A^{[n]}}^{[m]}
.
But, and this is what blocks just simply redefining setcol
when evaluated inside the macro setcol
, I want setcol{(setcol{A}{n} + B)}{m}
to evaluate to {({A}^{[n]}+B)}^{[m]}
.
So, basically I need to check if the argument to setcol
is a bare call to setcol
and do something different in that case. How can I do that? I feel there must be some kind of check with ifx
but I’m a bit fuzzy on that.
You can achieve this by testing whether the argument contains exactly 3 braced groups or tokens and if so whether the first of those tokens is setcol
. If that is the case output the special case, else use the normal output.
The following uses expl3
to achieve this (because it already contains everything we need for those tests).
documentclass[]{article}
ExplSyntaxOn
NewDocumentCommand setcol {m m}
{
bool_lazy_and:nnTF
{ int_compare_p:nNn { tl_count:n {#1} } = 3 }
{ tl_if_head_eq_meaning_p:nN {#1} setcol }
{
pgerdes_setcol_special:nnnn #1 {#2}
}
{
pgerdes_setcol_normal:nn {#1} {#2}
}
}
cs_new:Npn pgerdes_setcol_special:nnnn #1 #2 #3 #4
{
{#2} sp { [#3] [#4] }
}
cs_new:Npn pgerdes_setcol_normal:nn #1 #2
{
{#1} sp { [#2] }
}
ExplSyntaxOff
begin{document}
$setcol{A}{n}$
$setcol{setcol{A}{n}}{m}$
$setcol{(setcol{A}{n} + B)}{m}$
end{document}
Since you already had the idea to use ifx
, here is how I would've done it without expl3
(so this might be a bit more educational), the idea remains the same, test whether it's 3 tokens and the first one is setcol
.
documentclass[]{article}
makeatletter
newcommandsetcol[1]
{%
setcol@ifthree{#1}
{%
setcol@special#1{#1}%
}
{%
setcol@normal{#1}%
}%
}
newcommandsetcol@ifthree[1]
{%
ifnumnumexprsetcol@count#1setcol@stop=3
expandafter@firstoftwo
else
expandafter@secondoftwo
fi
}
newcommandsetcol@count[1]
{%
ifxsetcol@stop#1%
else
expandafter+expandafter1expandaftersetcol@count
fi
}
newcommandsetcol@special[5]
{%
ifxsetcol#1%
{#2}^{[#3][#5]}%
else
{#4}^{[#5]}%
fi
}
newcommandsetcol@normal[2]
{%
{#1}^{[#2]}%
}
newcommand*setcol@stop{setcol@stop}
makeatother
begin{document}
$setcol{A}{n}$
$setcol{setcol{A}{n}}{m}$
$setcol{(setcol{A}{n} + B)}{m}$
end{document}
(output like above)
Correct answer by Skillmon on March 25, 2021
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