TeX - LaTeX Asked by Abdulhameed on August 23, 2021
What is required to make this equation look better? I have tried my skills but the 0 does not align well.
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align}
R^* = begin{cases} 0 & dfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+frac{y^2u}{{pi}}right)}{y
lambda_{T}}+dfrac{u}{lambda_{X}}leq 0 sqrt{dfrac{lnleft(frac{yuv}{{pi}lambda_{T}}+frac{y^2u}{{pi}}right)}{y lambda_{T}}+dfrac{u}{lambda_{T}}} & dfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+frac{y^2u}{{pi}}right)}{y lambda_{X}}+dfrac{u}{lambda_{X}} > 0 end{cases}.
end{align}
end{document}
I propose to use medium-sized fractions, defined in nccmath
, and eqparbox
to centre the 0
w.r.t. the below square root:
documentclass{article}
usepackage{nccmath, mathtools}
usepackage{eqparbox, booktabs}
newcommandeqmathbox[2][M]{eqmakebox[#1]{$displaystyle#2$}}
begin{document}
begin{align}
R^* = begin{cases} eqmathbox{0} & text{if } mfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+frac{y^2u}{{pi}}right)}{y
lambda_{T}}+mfrac{u}{lambda_{X}}leq 0 , addlinespace[2ex] eqmathbox{sqrt{mfrac{lnleft(frac{yuv}{{pi}lambda_{T}}+frac{y^2u}{{pi}}right)}{y lambda_{T}}+mfrac{u}{lambda_{T}}}} & text{if }mfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+frac{y^2u}{{pi}}right)}{y lambda_{X}}+mfrac{u}{lambda_{X}} > 0 . end{cases}
end{align}
end{document}
Answered by Bernard on August 23, 2021
Maybe you can move the 0 a bit to the right, but the formula is awful to begin with, because the same complicated formula is typeset over and over again.
I suggest a much more economical version, under the assumption that all T's should be X's. Fix it, because the original doesn't seem correct.
documentclass{article}
usepackage{amsmath}
begin{document}
begin{equation}
R^* =
begin{cases}
quad 0 &
dfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+
frac{y^2u}{{pi}}right)}{ylambda_{T}}+dfrac{u}{lambda_{X}}leq 0
[4ex]
sqrt{dfrac{lnleft(frac{yuv}{{pi}lambda_{T}}+frac{y^2u}{{pi}}right)}{y lambda_{T}}
+dfrac{u}{lambda_{T}}} &
dfrac{lnleft(frac{yuv}{{pi}lambda_{X}}+frac{y^2u}{{pi}}right)}{y lambda_{X}}
+dfrac{u}{lambda_{X}} > 0
end{cases}.
end{equation}
begin{equation}
R^*=sqrt{maxleft{
0,
dfrac{1}{ylambda_{X}}lnleft(frac{yuv}{pilambda_{X}}+frac{y^2u}{pi}right)
+dfrac{u}{lambda_{X}}
right}}
end{equation}
end{document}
Answered by egreg on August 23, 2021
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