TeX - LaTeX Asked by firework on June 24, 2021
Source Code:
begin{align*}
& = frac{frac{a}{c} - frac{b}{d}}{frac{a}{c} + frac{b}{d}} - frac{a-b}{a+b} & = frac{alpha a - b}{alpha a + b} - frac{a-b}{a+b}
& = frac{2(alpha - 1)ab}{alpha a^2+(1+alpha)ab+b^2} & = frac{2(alpha - 1)}{alpha beta +(1+alpha) + frac{1}{beta}}
end{align*}
We can see that in the first row second column, the "=" is not aligned correctly with the second row.
You're not using the syntax of the align*
environment correctly: If you have more than one alignment point per row and wish the material in the second group to be aligned on the =
symbols instead of flush-right, you need to use &&=
, not &=
.
That said, I'd use an alignat*
environment instead of an align*
environment in order to avoid creating a needless gap between the two groups. Furthermorem, as @egreg has pointed out in a comment, there may not even be a need to align the right-hand set of equations on their =
symbols -- at least not for the sample equations you provided.
documentclass{article}
usepackage{amsmath,xcolor}
begin{document}
textcolor{red}{incorrect}
begin{align*}
&= frac{frac{a}{c}-frac{b}{d}}{frac{a}{c} + frac{b}{d}} - frac{a-b} {a+b}
&= frac{alpha a - b}{alpha a + b} - frac{a-b}{a+b}
&=frac{2(alpha - 1)ab}{alpha a^2+(1+alpha)ab+b^2}
&=frac{2(alpha - 1)}{alpha beta +(1+alpha) + frac{1}{beta}}
end{align*}
textcolor{red}{correct but unattractive}
begin{align*}
&= frac{frac{a}{c}-frac{b}{d}}{frac{a}{c} + frac{b}{d}} - frac{a-b} {a+b}
&&= frac{alpha a - b}{alpha a + b} - frac{a-b}{a+b}
&=frac{2(alpha - 1)ab}{alpha a^2+(1+alpha)ab+b^2}
&&=frac{2(alpha - 1)}{alpha beta +(1+alpha) + frac{1}{beta}}
end{align*}
textcolor{red}{better: use texttt{alignat*} instead of texttt{align*}}
begin{alignat*}{2}
&= frac{frac{a}{c}-frac{b}{d}}{frac{a}{c} + frac{b}{d}} - frac{a-b} {a+b}
&&= frac{alpha a - b}{alpha a + b} - frac{a-b}{a+b}
&=frac{2(alpha - 1)ab}{alpha a^2+(1+alpha)ab+b^2}
&&=frac{2(alpha - 1)}{alpha beta +(1+alpha) + frac{1}{beta}}
end{alignat*}
textcolor{red}{even better: don't align the second set of texttt{=} symbols}
begin{align*}
&= frac{frac{a}{c}-frac{b}{d}}{frac{a}{c} + frac{b}{d}} - frac{a-b} {a+b}
= frac{alpha a - b}{alpha a + b} - frac{a-b}{a+b}
&=frac{2(alpha - 1)ab}{alpha a^2+(1+alpha)ab+b^2}
=frac{2(alpha - 1)}{alpha beta +(1+alpha) + frac{1}{beta}}
end{align*}
end{document}
Correct answer by Mico on June 24, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP