Super User Asked on December 18, 2021
I can launch exe by specifying its path:
c:> "c:program files (x86)Microsoft Visual Studio2019CommunityCommon7IDEdevenv.exe"
, now trying doing the same with start
:
c:> start /separate "c:program files (x86)Microsoft Visual Studio2019CommunityCommon7IDEdevenv.exe"
will launch only another instance of cmd.exe
, but not visual studio. Does anyone know why?
If the first argument to start
is quoted, it is interpreted as the title of the window. So you need:
start /separate "" "c:program files (x86)Microsoft Visual Studio2019CommunityCommon7IDEdevenv.exe"
As Steve Rindsberg's comment indicates, I don't think you meant /separate
. It will likely be ignored on modern platforms.
Answered by David Schwartz on December 18, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP