Stack Overflow Asked by ddave on November 29, 2021
Hi i have following xml file
<?xml version="1.0"?>
<Company>
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
<Employee Name="Felix" Adress="Adress" age="22">
</Company>
I want to read it and get all names as an List. All Adress also as an List. All Ages also as an seperate List.
I have tried it with XDocument but i didnt figure it out how this should work.
I never know how long the list ist.
If I just get the whole string "<Employee Name="Felix" Adress="Adress" age="22"> " as one Listobject then i would just use a seperator but this not right to me.
I know there should be something to get a Attribut from a Node?
Thanks in advance
I want to build it in C#.
Linq is welcome
Try following :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = @"c:temptest.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
List<Employee> employee = doc.Descendants("Employee").Select(x => new Employee()
{
name = (string)x.Attribute("Name"),
address = (string)x.Attribute("Adress"),
age = (int)x.Attribute("age")
}).ToList();
List<string> names = employee.Select(x => x.name).ToList();
List<string> addresses = employee.Select(x => x.address).ToList();
List<int> ages = employee.Select(x => x.age).ToList();
}
}
public class Employee
{
public string name { get; set; }
public string address { get; set; }
public int age { get; set; }
}
}
Answered by jdweng on November 29, 2021
Answered by Z.D. on November 29, 2021
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