Stack Overflow Asked by saurabh on December 31, 2020
def r(s):
str = []
for i in len(s):
if (s[i]=='_'):
str = s[i] + str
continue
str = s[i] + str
return str
I tried using the above code to convert the following string
Input: ab_cde
Expected Output: ed_cba
def fixed_reverse(s, ch):
idxs = [-1] + [i for i, x in enumerate(s) if x == ch] + [len(s)]
idxs = [x - i + 1 for i, x in enumerate(idxs)]
chars = "".join(x for x in s if x != ch)[::-1]
return ch.join(chars[a:b] for a, b in zip(idxs[:-1], idxs[1:]))
>>> fixed_reverse("ab_cde_f_ghijk_l", "_")
'lk_jih_g_fedcb_a'
This works by:
"_"
."_"
characters removed."_"
back into the correct locations.Answered by Mateen Ulhaq on December 31, 2020
The main idea is to check all the positions of the underscore _
, save them and reverse the string without them, to insert them again after reversing.
import re
def r(s):
# check where all the underscore are
underscore_positions = [m.start() for m in re.finditer('_', s)]
# get list of reversed chars without underscores
reversed_chars = [c for c in reversed(s) if c != '_']
# put underscore back where they where
for p in underscore_positions:
reversed_chars.insert(p, '_')
# profit
return "".join(reversed_chars)
The function can be modified to have a different fixed character.
I also uses the package re
for the regex function to identify the _
, you can do with a simple loop as underscore_positions = [i for i, c in enumerate(s) if c =='_']
if you prefer.
Answered by bracco23 on December 31, 2020
s = 'ab_cde'
out = ''
for a, b in zip(s, s[::-1]):
if b != '_' and a != '_':
out += b
else:
out += a
print(out)
Prints:
ed_cba
EDIT: For more fixed points:
s = 'ab_cde_f_ghijk_l'
i, out = iter(ch for ch in s[::-1] if ch != '_'), ''
out = ''.join(ch if ch == '_' else next(i) for ch in s)
print(out)
Prints:
lk_jih_g_fedcb_a
Answered by Andrej Kesely on December 31, 2020
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