Stack Overflow Asked by Adam Sewell on August 28, 2020
I trying to split a string (although numbers currently a string in df column) but am struggling to find an answer anywhere. I think using expressions might be the way forward but haven’t quite got my head around them.
example 1) 12.540%
example 2) 4.555.6%
I would like to take everything to the left of the first ‘.’ and only one number going to the right of the same first ‘.’
I need to apply it to all different number lengths and the above statement is the only constant.
example 1 ) 12.5 and 40%
example 2) 4.5 and 55.6%
Thank you
The following function should do what you want:
def split_string(num):
s=num.split('.', 1)
s1=s[0]+'.'+s[1][0]
s2=s[1][1:]
return (s1, s2)
Correct answer by archer on August 28, 2020
If you want regular expressions, catch the groups using this.
^(d+..)(.*)$
Use this with either re.search if you want.
b = re.search(r'^(d+..)(.*)$', string)
b.group(1)
b.group(2)
Ex-
val = '12.445.6'
b = re.search(r'^(d+..)(.*)$', val)
b.group(1)
Out[24]: '12.4'
b.group(2)
Out[25]: '45.6'
Answered by Anurag Reddy on August 28, 2020
This is a straightforward problem in string manipulation. Any string tutorial will teach you the basic operations.
For instance, one you find the location loc
and adjust 1 or 2 spots to the right:
num, pct = str[:loc], str[loc:]
Answered by Prune on August 28, 2020
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