Python regex for numbers between 0-63

Question

I have written this regex to match the numbers in the aforementioned range but it's not working properly, for instance it matches "00" and "64", and I don't get why. My logic is "numbers between 0 or 9" or "numbers between 10-59" or numbers between "60-63".
import re

def six_bit_number(n):
    if re.match("([0-9]|[1-5][0-9]|6[0-3])", str(n)):
        return True
    return False

Perplexityy · Answer

In addition to Ry's answer, simply changing to
re.fullmatch

worked.

mishsx · Answer

Try the below regex:
^([0-9]|[1-5][0-9]|(6[0123]))$ [Include Global and Multiline flag]

Understanding of the regex:
[0-9] --> Matches single-digit numbers from 0 to 9
[1-5][0-9] --> Matches double digit numbers from 10 to 59
(6[0123]) --> Matches 60,61,62 and 63

Ry- · Answer

re.match looks for a match at the start of the input, but it doesn’t mind if there’s also text after the match. You can add an anchor to make sure it also checks for the end of the string:
r"([0-9]|[1-5][0-9]|6[0-3])Z"

Python regex for numbers between 0-63

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