Stack Overflow Asked by Catalina Hernández on February 20, 2021
I am trying to assign payments which are stored in p vector to the vector of debts which is l, so I need to store the dates of payment and the payed value for each date of payment, according the debts.
This code is for the payments for only the first debt ($254.000) (the position 0 in l):[62998, datetime.date(2019, 11, 29), 254000.0]
The desired results are:
But, when update the second last line "recuperados.append()" with the commented code "recuperados.append(‘a’)", the output of the first point change, the question is why?
The new output is:
fechas_rec=[datetime.date(2020, 2, 28), datetime.date(2020, 3, 30)]
Code:
l = [
[62998, datetime.date(2019, 11, 29), 254000.0],
[65317, datetime.date(2019, 12, 30), 229000.0],
[66606, datetime.date(2020, 1, 31), 229000.0],
[68751, datetime.date(2020, 2, 28), 228000.0],
[70652, datetime.date(2020, 3, 24), 229000.0],
]
p = [
[137500.0, datetime.date(2020, 1, 30)],
[126500.0, datetime.date(2020, 2, 28)],
[110000.0, datetime.date(2020, 3, 30)],
]
for j in l:
fechas_rec = []
recuperados = []
suma = 0
for i in enumerate(p):
suma = suma + i[1][0]
if suma <= j[2]:
fechas_rec.append(i[1][1])
recuperados.append(i[1][0])
else:
val = suma - j[2]
c = i[1]
del p[: i[0] + 1]
p.insert(0, [val, c[1]])
fechas_rec.append(i[1][1])
recuperados.append() # recuperados.append('a')
break
Code:
l = [
[62998, datetime.date(2019, 11, 29), 254000.0],
[65317, datetime.date(2019, 12, 30), 229000.0],
[66606, datetime.date(2020, 1, 31), 229000.0],
[68751, datetime.date(2020, 2, 28), 228000.0],
[70652, datetime.date(2020, 3, 24), 229000.0],
]
p = [
[137500.0, datetime.date(2020, 1, 30)],
[126500.0, datetime.date(2020, 2, 28)],
[110000.0, datetime.date(2020, 3, 30)],
]
for j in l:
fechas_rec=[]
recuperados=[]
suma=0
for i in enumerate(p):
suma1=suma
suma=suma+i[1][0]
if suma<=j[2]:
fechas_rec.append(i[1][1])
recuperados.append(i[1][0])
else:
val=suma-j[2]
c=i[1]
del p[:i[0]+1]
p.insert(0,[val,c[1]])
fechas_rec.append(i[1][1])
recuperados.append(j[2]-suma1)
break
drec.append([j[0],fechas_rec,recuperados])
sumtot=sumtot+sum(drec[-1][2])
if sumtot==rectot:
test=True
if test:
break
Answered by Catalina Hernández on February 20, 2021
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