invalid initializer for rand() when assigning to array

Question

#include #include int main(){ int n; for(int i= 0;i < 5; i++ ){ //type arrayName[arraysize]; int arrayName[5] = rand(); printf("array[%d] = %dn",i,arrayName[i]); } return 0; } I got an error about an invalid initializer for rand(); How do I add a random to the array and give it a range?

Rohan Kumar · Answer

You're missing two things here:

You haven't declared the array you intend to use. Declare it like this:

int arrayName[5];

rand() call doesn't return integer array, it just return one integer. So you would want to replace this:

int arrayName[5] = rand();

with this:
arrayName[i] = rand();

Ali Mirghasemi · Answer

remember you can't initialize an array with random variables like that you must fill item by item

array[i] = rand();

you need to just change your place of define variables like this

#include <stdio.h>
#include <stdlib.h>
int main(){
    int arrayName[5];
    int n;
    int i;
    for(i = 0;i < 5; i++ ){
        arrayName[i] = rand();
        printf("array[%d] = %dn",i,arrayName[i]);
    }
    return 0;
}

and this is a function that fill an array with random numbers

void generateFunction(int* arr, int len) {
    while (len-- > 0) {
        *arr++ = rand();
    }
}

or in simple way

void generateFunction(int* arr, int len) {
    int i;
    for (i = 0; i < len; i++) {
        arr[i] = rand();
    }
}

invalid initializer for rand() when assigning to array

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