Stack Overflow Asked on November 7, 2021
Say I have a string tex = "somestring"
I need to create a loop that will create multiple copies of that string, each one with a period added after a character, starting after the first character and ending it before the last
Something like
for i in range (1, len(tex)-2):
tex = ....
print(tex)
The output needs to be:
s.omestring
so.mestring
som.estring
...
somestrin.g
I tried using tex = '.'.join(tex[i+1] for i in range (1, len(tex)-2, 1))
from other questions but that adds a period after every character only once, resulting in s.o.m.e.s.r.i.n.g
Maybe splitting the string into a list of characters would help, but I’m not sure how to approach it from that way.
text = "something"
for char in range(1, len(text)):
print(text[:char] + "." + text[char:])
Hope i was helpful!
Answered by Talico17 on November 7, 2021
Simply use this -
for i in range (1, len(tex)):
print(tex[:i]+"."+tex[i:])
Answered by kuro on November 7, 2021
Here is a possible one line solution:
s = 'somestring'
print(*(s[:i] + '.' + s[i:] for i in range(1, len(s))), sep='n')
Output:
s.omestring
so.mestring
som.estring
some.string
somes.tring
somest.ring
somestr.ing
somestri.ng
somestrin.g
Answered by Riccardo Bucco on November 7, 2021
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