Stack Overflow Asked by Arthur Adrian on December 13, 2021
I have a Map<Datetime, List> in Dart that stores events needed to fill up a calendar in my Flutter app:
final Map<DateTime, List> _events = {
DateTime(2020, 7, 7): [
{'name': 'Event A', 'isDone': true},
],
DateTime(2020, 7, 11): [
{'name': 'Event A', 'isDone': true}
],
DateTime(2020, 7, 9): [
{'name': 'Event A', 'isDone': true},
{'name': 'Event B', 'isDone': true},
],
DateTime(2020, 7, 10): [
{'name': 'Event A', 'isDone': true},
{'name': 'Event B', 'isDone': true},
],
DateTime(2020, 7, 13): [
{'name': 'Event A', 'isDone': true},
{'name': 'Event B', 'isDone': true},
{'name': 'Event C', 'isDone': false},
],
DateTime(2020, 7, 25): [
{'name': 'Event A', 'isDone': true},
{'name': 'Event B', 'isDone': true},
{'name': 'Event C', 'isDone': false},
],
DateTime(2020, 7, 6): [
{'name': 'Event A', 'isDone': false},
],
};
I want to convert this into JSON but I’m not entirely sure how to model the class. Anyone got any ideas?
If you simply want to convert this to a JSON you can use the jsonEncode
function and use the toEncodable
named parameter to allow your object to be encoded. I made an example here that just cast the keys of your Map
to a String
so that it can be encoded.
jsonEncode(
_events,
toEncodable: (input) {
return _events.map((key, value) {
return MapEntry(key.toString(), value);
});
}
);
When you want to decode this back to your Map<DateTime, List>
you can just do the reverse.
var objectTemp = jsonDecode(
json,
);
var output = objectTemp.map((key, value) {
return MapEntry(DateTime.parse(key), value);
})
Answered by Christopher Moore on December 13, 2021
Create a model class for Event
and store the event data in it (name, isDone and date). Then you put them in a List<Event>
. You can search on this list for a spesific date and get the according events if any. Then you can make that data class serializable.
Answered by easeccy on December 13, 2021
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