Stack Overflow Asked by icedcoffee on January 29, 2021
I have an object mydf
:
mydf <- structure(list(USUBJID = structure(c("ID1", "ID2",
"ID3", "ID4", "ID5",
"ID6"), label = "ID"), MYDATE = structure(c("2012-03-06",
"2013-04-09", "2014-06-11", "2011-03-24", "2018-01-08", "2010-03-14"
), label = "Date")), row.names = c("1", "2",
"3", "4", "5",
"6"), class = "data.frame")
> mydf
USUBJID MYDATE
1 ID1 2012-03-06
2 ID2 2013-04-09
3 ID3 2014-06-11
4 ID4 2011-03-24
5 ID5 2018-01-08
6 ID6 2010-03-14
sapply(mydf, class)
USUBJID MYDATE
"character" "character"
attributes(mydf$MYDATE)$label
[1] "Date"
When I convert mydf$MYDATE to class Date as follows:
mydf <- mydf %>% mutate(
MYDATE = as.Date(MYDATE)
)
sapply(mydf, class)
USUBJID MYDATE
"character" "Date"
attributes(mydf$MYDATE)$label
NULL
It looses the label attribute. How can I convert it to Date, but without removing the label attribute?
You can use []
like:
mydf$MYDATE[] <- as.Date(mydf$MYDATE)
class(mydf$MYDATE) <- "Date"
attributes(mydf$MYDATE)$label
#[1] "Date"
class(mydf$MYDATE)
#[1] "Date"
Answered by GKi on January 29, 2021
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