Stack Overflow Asked by Pratik Goud on September 13, 2020
def change(a):
a=4
print('1:')
c=3
print('Value before changing',c)
change(c)
print('Value after changing',c)
print('2:')
d=6
print('Value before changing',d)
change(d)
print('Value after changing',d)
print('3:')
e=7
print('Value before changing',e)
change(e)
print('Value after changing',e)
I want to change n distinct global variables. Eg: I want to change c,d and e global variables using function by passing it as a argument. How can I do so?
I've updated my previous answer so that it should work, but here is an alternative method.
def change(**kwargs):
for name in kwargs:
globals()[name] = 4
x = 3
change(x=x) # whatever follows the '=' sign is redundant in this case
Or, you could do
def change(**kwargs):
globals().update(kwargs)
x = 3
change(x=4) # the global value of 'x' is now 4
Answered by Marcus Weinberger on September 13, 2020
the global keyword tells the function that there already exists a variable of this name, defined outside the current scope. It is in, what python calls, the global scope (think the outter-most scope of a python file).
>>> def change(a, value=4):
global a
a = value
>>> x = 3
>>> change(x)
# x = 4
Answered by rnath on September 13, 2020
Edit:
My original answer wouldn't have worked. So here's my new answer. First, you'll need a function to get the name of the variable. This can be done with the builtin inspect
package like so,
import inspect
def retrieve_name(var):
callers_local_vars = inspect.currentframe().f_back.f_locals.items()
return [var_name for var_name, var_val in callers_local_vars if var_val is var]
Then, you'll need to rewrite your change function to
def change(a):
globals()[a] = 4
And use it in conjunction with the retrieve_name
function like so,
change(retrieve_name(x)[0])
Because if you just put the retrieve_name
inside change
it will always return a
.
Below is my original answer:
Tell the function change
that a
is global. Eg:
def change(a):
global a
a = 4
Answered by Marcus Weinberger on September 13, 2020
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