Stack Overflow Asked by Trajce12 on November 22, 2021
I have this kind of json.
let arr1 = [
{
"packageReference": "1234",
"displayName": "Business",
"description": "Includes...",
"promotion": {
"packageReference": "1234",
"displayName": "$100 Standard",
"optionGroup": [
{
"displayName": "Access",
},
{
"displayName": "Contract"
},
{
"displayName": "Equipment"
},
{
"displayName": "Features"
},
{
"displayName": "Fees",
}
]
}
}
]
I need to remove only the object in the arr1[0].promotion.optionGroup where the displayName is ‘Fees’ and to return the new object without him.
// Get new array without the Fees one
const newGroup = arr1[0].promotion.optionGroup.filter(group => group.displayName !== 'Fees');
// Put new group into the object
arr1[0].promotion.optionGroup = newGroup;
Could also do it without creating a variable, but added it for cleanness.
Answered by Emre Koc on November 22, 2021
You could do it by filtering the sub array like so:
let arr1 = [
{
"packageReference": "1234",
"displayName": "Business",
"description": "Includes...",
"promotion": {
"packageReference": "1234",
"displayName": "$100 Standard",
"optionGroup": [
{
"displayName": "Access",
},
{
"displayName": "Contract"
},
{
"displayName": "Equipment"
},
{
"displayName": "Features"
},
{
"displayName": "Fees",
}
]
}
}
];
arr1 = arr1.map(e => {
e['promotion']['optionGroup'] =
e['promotion']['optionGroup'].filter(s => s['displayName'] != 'Fees');
return e;
});
console.log(arr1);
Answered by MauriceNino on November 22, 2021
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