Deleting from array using unset creates values

Question

$array = [ 0, 5, 7 ];

For this array, I want to unset without it assigning a value.
When I unset($array[5]) it will return
{
    "0" => 0,
    "1" => 5,
    "2" => 7
}

But my actual goal is to make it return like
[ 0, 7 ]
That way when I use json_encode it will just show up as
[ 
    0,
    7
]

Is this possible at all? I googled and everyone just mentions indexing, but I am looking at just removing this number from the array. Not have it reindex or change the formatting of it to have a value.

SirPilan · Answer

$a = [0,5,7];
array_splice($a, 1, 1); // remove from position 1 - remove 1 entry

echo json_encode($a);

Working example.
output
[0,7]

references

array_splice

additional informaion
Unset wont work as is, since it preserves the initial keys.
A solution with unset is to ignore the keys by using array_values:
$a = [0,5,7];

unset($a[1]);
$a = array_values($a);

echo json_encode($a);

Working example.
Same output as above.

maio290 · Answer

The parameter within the brackets on $array[] is actually the numerical index or associative index (arrays in PHP are maps).
In your case, you want to do:
unset($arr[1]);

Deleting from array using unset creates values

2 Answers

output

references

additional informaion

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