Stack Overflow Asked by Brian Yeh on January 11, 2021
Below is an error
std::mutex mtx;
auto t = std::make_pair(std::string("hello"), mtx);
But the following is not?
std::mutex mtx;
auto t = std::make_pair(std::string("hello"), 1);
My ultimate goal is to create a create an unordered map of type:
std::unordered_map<std::string, std::mutex>
Using:
mHeartBeatMutexes.insert(std::make_pair(std::string("hello"), mtx));
But my IDE is saying it’s wrong and I’m not sure why.
std::mutex
is not copyable or moveable. When you do
std::mutex mtx;
auto t = std::make_pair(std::string("hello"), mtx);
and
mHeartBeatMutexes.insert(std::make_pair(std::string("hello"), mtx));
std::make_pair
tries to make a copy of mtx
since it is an lvalue and it can't because std::mutex
is not copyable.
In
std::mutex mtx;
auto t = std::make_pair(std::string("hello"), 1);
1
is an integer literal which materializes into a temporary integer that is moved (copy really as it's the same thing) and that's all good.
To put a mutex into a std::unordered_map<std::string, std::mutex>
what you need to do is use the emplace function to directly create the pair inside the unordered_map
leverage the std::piecewise_construct
overload and std::forward_as_tuple
to build the arguments for each member of the pair's constructor like
std::unordered_map<std::string, std::mutex> foo;
foo.emplace(std::piecewise_construct,
std::forward_as_tuple("hello"),
std::forward_as_tuple());
Correct answer by NathanOliver on January 11, 2021
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