Stack Overflow Asked by Nithin K Anil on January 28, 2021
I am creating a AWS Lambda python deployment package. I am using one external dependency requests . I installed the external dependency using the AWS documentation http://docs.aws.amazon.com/lambda/latest/dg/lambda-python-how-to-create-deployment-package.html. Below is my python code.
import requests
print('Loading function')
s3 = boto3.client('s3')
def lambda_handler(event, context):
#print("Received event: " + json.dumps(event, indent=2))
# Get the object from the event and show its content type
bucket = event['Records'][0]['s3']['bucket']['name']
key = urllib.unquote_plus(event['Records'][0]['s3']['object']['key']).decode('utf8')
try:
response = s3.get_object(Bucket=bucket, Key=key)
s3.download_file(bucket,key, '/tmp/data.txt')
lines = [line.rstrip('n') for line in open('/tmp/data.txt')]
for line in lines:
col=line.split(',')
print(col[5],col[6])
print("CONTENT TYPE: " + response['ContentType'])
return response['ContentType']
except Exception as e:
print(e)
print('Error getting object {} from bucket {}. Make sure they exist and your bucket is in the same region as this function.'.format(key, bucket))
raise e
Created the Zip the content of the project-dir directory and uploaded to the lambda(Zip the directory content, not the directory). When I am execute the function I am getting the below mentioned error.
START RequestId: 9e64e2c7-d0c3-11e5-b34e-75c7fb49d058 Version: $LATEST
**Unable to import module 'lambda_function': No module named lambda_function**
END RequestId: 9e64e2c7-d0c3-11e5-b34e-75c7fb49d058
REPORT RequestId: 9e64e2c7-d0c3-11e5-b34e-75c7fb49d058 Duration: 19.63 ms Billed Duration: 100 ms Memory Size: 128 MB Max Memory Used: 9 MB
Kindly help me to debug the error.
Error was due to file name of the lambda function. While creating the lambda function it will ask for Lambda function handler. You have to name it as your Python_File_Name.Method_Name. In this scenario I named it as lambda.lambda_handler (lambda.py is the file name).
Correct answer by Nithin K Anil on January 28, 2021
The issue here that the Python version used to build your Lambda function dependencies (on your own machine) is different than the selected Python version for your Lambda function. This case is common especially if the Numpy library part of your dependencies.
Example: Your machine's python version: 3.6 ---> Lambda python version 3.6
Answered by Sharhabeel Hamdan on January 28, 2021
Please add below one after Import requests
import boto3
What I can see that is missing in your code.
Answered by Mrinal on January 28, 2021
Actually go to the main folder (deployment package)that you want to zip,
Inside that folder select all files and then create the zip and upload that zip
Answered by MUHAMMAD ZEESHAN on January 28, 2021
My problem was that the .py file and dependencies were not in the zip's "root" directory. e.g the path of libraries and lambda function .py must be:
<lambda_function_name>.py
<name of library>/foo/bar/
not
/foo/bar/<name of library>/foo2/bar2
For example:
drwxr-xr-x 3.0 unx 0 bx stor 20-Apr-17 19:43 boto3/ec2/__pycache__/
-rw-r--r-- 3.0 unx 192 bx defX 20-Apr-17 19:43 boto3/ec2/__pycache__/__init__.cpython-37.pyc
-rw-r--r-- 3.0 unx 758 bx defX 20-Apr-17 19:43 boto3/ec2/__pycache__/deletetags.cpython-37.pyc
-rw-r--r-- 3.0 unx 965 bx defX 20-Apr-17 19:43 boto3/ec2/__pycache__/createtags.cpython-37.pyc
-rw-r--r-- 3.0 unx 7781 tx defN 20-Apr-17 20:33 download-cs-sensors-to-s3.py
Answered by lobi on January 28, 2021
Make sure that you are zipping all dependencies in a folder structure as python/[Your All Dependencies] to make it work as per this documentation.
https://docs.aws.amazon.com/lambda/latest/dg/configuration-layers.html#configuration-layers-path
Answered by Sachin Kumar on January 28, 2021
You can configure your Lambda function to pull in additional code and content in the form of layers. A layer is a ZIP archive that contains libraries, a custom runtime, or other dependencies. With layers, you can use libraries in your function without needing to include them in your deployment package. Layers let you keep your deployment package small, which makes development easier.
References:-
Answered by Rahul Satal on January 28, 2021
Sharing my solution for the same issue, just in case it helps anyone.
Issue: I got error: "[ERROR] Runtime.ImportModuleError: Unable to import module 'lambda_function': No module named 'StringIO'" while executing aws-big-data-blog code[1] provided in AWS article[2].
Solution: Changed Runtime from Python 3.7 to Python 2.7
[1] — https://github.com/bsnively/aws-big-data-blog/blob/master/aws-blog-vpcflowlogs-athena-quicksight/CloudwatchLogsToFirehose/lambdacode.py [2] — https://aws.amazon.com/blogs/big-data/analyzing-vpc-flow-logs-with-amazon-kinesis-firehose-amazon-athena-and-amazon-quicksight/
Answered by user72789 on January 28, 2021
Here's a quick step through.
Assume you have a folder called deploy
, with your lambda file inside call lambda_function.py
. Let's assume this file looks something like this. (p1
and p2
represent third-party packages.)
import p1
import p2
def lambda_handler(event, context):
# more code here
return {
"status": 200,
"body" : "Hello from Lambda!",
}
For every third-party dependency, you need to pip install <third-party-package> --target .
from within the deploy
folder.
pip install p1 --target .
pip install p2 --target .
Once you've done this, here's what your structure should look like.
deploy/
├── lambda_function.py
├── p1/
│ ├── __init__.py
│ ├── a.py
│ ├── b.py
│ └── c.py
└── p2/
├── __init__.py
├── x.py
├── y.py
└── z.py
Finally, you need to zip
all the contents within the deploy
folder to a compressed file. On a Mac or Linux, the command would look like zip -r ../deploy.zip *
from within the deploy
folder. Note that the -r
flag is for recursive subfolders.
The structure of the file zip file should mirror the original folder.
deploy.zip/
├── lambda_function.py
├── p1/
│ ├── __init__.py
│ ├── a.py
│ ├── b.py
│ └── c.py
└── p2/
├── __init__.py
├── x.py
├── y.py
└── z.py
Upload the zip file and specify the <file_name>.<function_name>
for Lambda to enter into your process, such as lambda_function.lambda_handler
for the example above.
Answered by openwonk on January 28, 2021
A perspective from 2019:
AWS Lambda now supports Python 3.7, which many people (including myself) choose to use as the runtime for inline lambdas.
Then I had to import an external dependency and I followed AWS Docs as the OP referred to. (local install --> zip --> upload).
I had the import module error and I realised my local PC had Python 2.7 as the default Python. When I invoked pip, it installed my dependency for Python 2.7.
So I switched locally to the Python version that matches the selected runtime version in the lambda console and then re-installed the external dependencies. This solved the problem for me. E.g.:
$ python3 -m pip install --target path/to/lambda_file <external_dependency_name>
Answered by l001d on January 28, 2021
In lambda_handler
the format must be lambda_filename.lambda_functionName
.
Supposing you want to run the lambda_handler
function and it's in lambda_fuction.py
, then your handler format is lambda_function.lambda_handler
.
Another reason for getting this error is module dependencies.
Your lambda_fuction.py
must be in the root directory of the zip file.
Answered by PKP on January 28, 2021
@nithin,
AWS released layers
concept inside Lambda
functions. You can create your layer and there you can upload as much as libraries and then you can connect the layer with the lambda functions.
For more details: https://docs.aws.amazon.com/lambda/latest/dg/configuration-layers.html
Answered by muTheTechie on January 28, 2021
You need to zip all the requirements, use this script
#!/usr/bin/env bash
rm package.zip
mkdir package
pip install -r requirements.txt --target package
cat $1 > package/lambda_function.py
cd package
zip -r9 "../package.zip" .
cd ..
rm -rf package
use with:
package.sh <python_file>
Answered by Uri Goren on January 28, 2021
I ran into the same issue, this was an exercise as part of a tutorial on lynda.com if I'm not wrong. The mistake I made was not selecting the runtime as Python 3.6 which is an option in the lamda function console.
Answered by Nadeem on January 28, 2021
No need to do that mess.
use python-lambda
https://github.com/nficano/python-lambda
with single command pylambda deploy
it will automatically deploy your function
Answered by softmarshmallow on January 28, 2021
I had the error too.
Turn out that my zip file include the code parent folder. When I unzip
and inspect the zip file, the lambda_function
file is under parent folder ./lambda
.
Use the zip
command, fix the error:
zip -r ../lambda.zip ./*
Answered by Joe on January 28, 2021
I found this hard way after trying all of the solutions above. If you're using sub-directories in the zip file, ensure you include the __init__.py
file in each of the sub-directories and that worked for me.
Answered by KApuri on January 28, 2021
If you are uploading a zip file. Make sure that you are zipping the contents of the directory and not the directory itself.
Answered by 2ank3th on January 28, 2021
There are just so many gotchas when creating deployment packages for AWS Lambda (for Python). I have spent hours and hours on debugging sessions until I found a formula that rarely fails.
I have created a script that automates the entire process and therefore makes it less error prone. I have also wrote tutorial that explains how everything works. You may want to check it out:
Answered by joarleymoraes on January 28, 2021
Another source of this problem is the permissions on the file that is zipped. It MUST be at least world-wide readable. (min chmod 444
)
I ran the following on the python file before zipping it and it worked fine.
chmod u=rwx,go=r
Answered by Catalin Ciurea on January 28, 2021
I found Nithin's answer very helpful. Here is a specific walk-through:
Look-up these values:
With these values, you would need to rename the handler (shown in the screenshot) to "cool.lambda_handler". This is one way to get rid of the "Unable to import module 'lambda_function'" errorMessage. If you were to rename the handler in your python script to "sup" then you'd need to rename the handler in the lambda dashboard to "cool.sup"
Answered by user3303554 on January 28, 2021
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