Stack Overflow Asked by CodeMaster on January 14, 2021
I have a dataframe with three columns; entity, date, value.
First I must order the ‘value’ based on ‘Descending order of ‘DATE” per entity.
Then,the requirement is to get 2 types of averages per entity based on the user defined number of rows. For example, if user enters 3 and 6; it means that ‘give me the average of first 3 values and then average of next 6 values‘ per entity.
for the given dataset, result would be a data frame as:
Entity Avg3 Avg6
A 110 65
B 220 130
I can use ‘aggregate
‘ function to get ‘mean
‘ by entity but I am not able to extract specific rows data per entity.
Also, ordering
the dataframe based on entity and then ‘date’ seems to not work.
#order data based on date (tried adding entity here but it does not work)
df_new <- df[rev(order(as.Date(df$Date)))),]
here is the dput:
structure(list(Wells = c("A", "A", "A", "A", "A", "A", "A", "A",
"A", "A", "A", "A", "B", "B", "B", "B", "B", "B", "B", "B", "B",
"B", "B", "B"), Date = structure(c(1577836800, 1577923200, 1578009600,
1578096000, 1578182400, 1578268800, 1578355200, 1578441600, 1578528000,
1578614400, 1578700800, 1578787200, 1577836800, 1577923200, 1578009600,
1578096000, 1578182400, 1578268800, 1578355200, 1578441600, 1578528000,
1578614400, 1578700800, 1578787200), class = c("POSIXct", "POSIXt"
), tzone = "UTC"), Index = c(10, 20, 30, 40, 50, 60, 70, 80,
90, 100, 110, 120, 20, 40, 60, 80, 100, 120, 140, 160, 180, 200,
220, 240)), row.names = c(NA, -24L), class = c("tbl_df", "tbl",
"data.frame"))
Here is an option with tidyverse
. Assuming we have dynamic inputs ('n1', 'n2'), arrange
the data by 'Wells' and in desc
ending order of 'Date', group_by
the 'Well', use slice_head
to get the first (n1 + n2
) rows, then summarise
to create the 'Avg' mean
columns by taking the head
and tail
of 'Index' based on the 'n1' and 'n2' respectively
library(dplyr)
library(stringr)
n1 <- 3
n2 <- 6
df %>%
arrange(Wells, desc(Date)) %>%
group_by(Wells) %>%
slice_head(n = n1 + n2) %>%
summarise(!! str_c('Avg', n1) := mean(head(Index, n1)),
!! str_c('Avg', n2) := mean(tail(Index, n2)), .groups = 'drop')
-output
# A tibble: 2 x 3
# Wells Avg3 Avg6
# <chr> <dbl> <dbl>
#1 A 110 65
#2 B 220 130
Or using base R
df1 <- df[order(df$Wells, -as.numeric(df$Date)),]
out <- do.call(data.frame, aggregate(Index ~ Wells,
subset(df1, ave(seq_along(Wells),
Wells, FUN = seq_along) <= (n1 + n2)), FUN = function(x)
c(Avg3 = mean(head(x, n1)), Avg6 = mean(tail(x, n2)))))
Correct answer by akrun on January 14, 2021
You can use cut
/findInterval
to divide data into groups, take mean
of each group and get data in wide format using pivot_wider
.
library(dplyr)
n <- c(3, 6)
df %>%
arrange(Wells, desc(Date)) %>%
group_by(Wells) %>%
group_by(grp = findInterval(row_number(), cumsum(n), left.open = TRUE), .add = TRUE) %>%
#For older dplyr version use add = TRUE
#group_by(grp = findInterval(row_number(), cumsum(n), left.open = TRUE), add = TRUE) %>%
summarise(Index = mean(Index)) %>%
slice(seq_along(n)) %>%
mutate(grp = paste0('avg', n)) %>%
tidyr::pivot_wider(names_from = grp, values_from = Index)
# Wells avg3 avg6
# <chr> <dbl> <dbl>
#1 A 110 65
#2 B 220 130
Answered by Ronak Shah on January 14, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP