Stack Overflow en español Asked on November 4, 2021
Tengo un archivo pickle que representa preguntas y respuestas en un formato diccionario y me gustaria saber donde estan los que estan grid de preguntas como la siguiente para puestarlas en un csv como gcoronel99 lo hicé aqui:
La estructura de este ejemplo esta como la siguente:
{'question': 'To what extent are the following factors considerations in your choice of flight? ',
'answers': [None,
7,
[[514996986,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['The airline/company you fly with'],
None,
None,
None,
None,
None,
None,
None,
[1]],
[396483948,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['The departure airport'],
None,
None,
None,
None,
None,
None,
None,
[1]],
[971070641,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['Duration of flight/route'],
None,
None,
None,
None,
None,
None,
None,
[1]],
[1685960105,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['Price'],
None,
None,
None,
None,
None,
None,
None,
[1]],
[231217486,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['Baggage policy'],
None,
None,
None,
None,
None,
None,
None,
[1]],
[940990935,
[['Very important consideration'],
['Important consideration'],
['Neutral'],
['Not an important consideration'],
['Do not consider']],
0,
['Environmental impacts'],
None,
None,
None,
None,
None,
None,
None,
[1]]]]}
Pero para los demas (si ya existen) pueden variar en funcion de la lineas o columnas. En el caso general pienso que una grid se reconoce cuando hay, en las answers
multiples tabulas de tabulas de tabulas.
Entonces intenté saber si funciona a lo menos con el ejemplo arriba:
import pickle
dic = pd.read_pickle(r'Python/interns.p')
def isGrid(qa):
d_answers = qa['answers']
# print("qa['question']: ", qa['question'])
if qa['question'] == 'To what extent are the following factors considerations in your choice of flight?':
try:
print("qa['question']: ", qa['question'])
answers = d_answers[2]
if len(answers)>1:
print(True)
return True
except TypeError:
print("truc")
for qa_set in dic:
for qa in qa_set:
bool_grid = isGrid(qa)
Pero obtengo:
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-1062-6d260b7f25bc> in <module>
18 for qa_set in dic:
19 for qa in qa_set:
---> 20 bool_grid = isGrid(qa)
21
22 # isGrid(qa)
<ipython-input-1062-6d260b7f25bc> in isGrid(qa)
4
5 def isGrid(qa):
----> 6 d_answers = qa['answers']
7 # print("qa['question']: ", qa['question'])
8 if qa['question'] == 'To what extent are the following factors considerations in your choice of flight?':
TypeError: string indices must be integers
Primero revisemos que implica iterar sobre un diccionario:
for key in dic:
print(key)
Se pensaría que este ciclo imprimiría cada par ordenado del diccionario, algo así:
question: To what extent are the following factors considerations in your choice of flight?
answers: [None, 7, [[514996986, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['The airline/company you fly with'], None, None, None, None, None, None, None, [1]], [396483948, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['The departure airport'], None, None, None, None, None, None, None, [1]], [971070641, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['Duration of flight/route'], None, None, None, None, None, None, None, [1]], [1685960105, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['Price'], None, None, None, None, None, None, None, [1]], [231217486, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['Baggage policy'], None, None, None, None, None, None, None, [1]], [940990935, [['Very important consideration'], ['Important consideration'], ['Neutral'], ['Not an important consideration'], ['Do not consider']], 0, ['Environmental impacts'], None, None, None, None, None, None, None, [1]]]]
¿Qué pasa realmente?
Realmente solo imprime los valores de las llaves como los strings que son:
question
answers
Entonces el ciclo anidado de
for qa_set in dic:
for qa in qa_set:
bool_grid = isGrid(qa)
Esta ejecutando la función, con cada letra de ambas palabras. Esto se puede comparar imprimiendo el valor de qa
por pantalla:
for qa_set in dic:
for qa in qa_set:
print(qa)
muestra
q
u
e
s
t
i
o
n
a
n
s
w
e
r
s
Entonces el error en la linea d_answers = qa['answers']
tiene sentido ahora. La letra individual es un string y se está intentando acceder a una llave como si fuera un diccionario. En otras plabras lo ocurre es esto:
d_answers = "q"['answers']
Por esto mismo ocurre el error
TypeError: string indices must be integers
los string no tiene llaves, solo indices. El primer error que obtienes se da debido al segundo.
isGrid()
funciona?La respuesta es que no, en el condicional
if qa['question'] == 'To what extent are the following factors considerations in your choice of flight?':
Estás evaluando si esa llave es igual a ese string, si te fijas en el diccionario dic
el valor de la llave ["question"]
es este string que evaluas, pero con un espacio al final. Para no modificar los datos la solución sería esta:
if qa['question'].strip() == 'To what extent are the following factors considerations in your choice of flight?':
Debido a que el método .strip()
elimina los espacios al final y principio de una cadena.
dic
?A mi punto de vista no, debido a que en la función se opera con ambos pares ordenados del diccionario. Solo basta con usar como parámetro de la función a dic
.
La función:
def isGrid(qa):
d_answers = qa['answers']
if qa['question'].strip() == 'To what extent are the following factors considerations in your choice of flight?':
try:
print("qa['question']: ", qa['question'])
answers = d_answers[2]
if len(answers) > 1:
print(True)
return True
except TypeError:
print("truc")
Usando a dic
como parámetro:
isGrid(dic)
devolvería
qa['question']: To what extent are the following factors considerations in your choice of flight?
True
Claramente tendrás tus razones para realizar esa iteración, no sé que tienes en el picke. Sin embargo, al menos ya sabes por que se produce tu error.
Answered by user166844 on November 4, 2021
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