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Relation between Jordan-Wigner transformation and Hilbert-Schmidt inner product

Quantum Computing Asked on August 13, 2021

Given a fermionic Hamiltonian in a matrix form, we can write it as a sum over Kronecker products of Pauli matrices using the Hilbert-Schmidt inner product. However if the same Hamiltonian is given in a operator form, we can use the Jordan-Wigner transformation to write it as a sum over Kronecker products of Pauli operators.

How can one show that both the methods will give the same result, or if that is not the case then how does one show that the two results are related in some way?

Any material that discusses this is also appreciated.

One Answer

It's a good question, but the answer is that the Hilbert-Schmidt inner product and the Jordan-Wigner transformation are not the same, even for the special case of fermionic Hamiltonians.

First let us consider spin-5/2 particles (they are still fermions). The fermionic Hamiltonian in this case will be $6^n times 6^n$ matrix for $n$ particles, so for one spin-5/2 particle we have a 6x6 matrix which cannot be decomposed as a Kronecker product of 2x2 Pauli matrices.

Now let me also mention that the Jordan-Wigner transformation is not the only way to convert a fermionic Hamiltonian into into a "Paulinomial" (polynomial of Pauli matrices). There's also, for example, the Bravyi-Kitaev transformation which will give a completely different Paulinomial compared to the Jordan-Wigner transformation, even when starting from the same fermionic Hamiltonian in operator form. Yet another example separate from the Jordan-Wigner and Bravyi-Kitaev bases is the parity basis (see Eqs 20-21 here).

Correct answer by user1271772 on August 13, 2021

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