Quantum Computing Asked by Anurag Singla on January 4, 2021
Suppose you have a quantum state $|wrangle$ consisting of $m + n$ qubits, and you set up a measurement that measures the first $m$ qubits in the standard basis. What are the matrices in the corresponding POVM?
Well, since these are projective measurements on the subspace of the first $m$ qubits, we can just list all projectors on the computational basis of this first subspace and 'pad' them with $I$'s on the second subspace:
$$ P_{j} = |jranglelangle j|_{m} otimes I_{|n|},,,, forall j in {0,1}^{m}, $$ which gives exactly $|{0,1}^{m}| = 2^{m}$ different operators for the POVM. If you identify distinct measurement outcomes with every operator, say $lambda_{j} = j_{d}$ (e.g. $j$ in decimal form), you can easily write down a measurement operator as well:
$$ M = sum_{j} lambda_{j}P_{j} = sum_{j} j_{d}|jrangle langle j otimes I_{n}| $$
See also, for instance, this nice answer by Daftwullie for a different measurement operator. Note that that answer omits the extra subspace of $n$, but you can just treat that by padding with $I$'s again.
Correct answer by JSdJ on January 4, 2021
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