TransWikia.com

How is this expression for a GHZ state obtained in the nature paper by Pan et al. (2000)?

Quantum Computing Asked by Haxhi Pantina on July 21, 2021

Can someone tell me how the authors of the paper "Experimental test of quantum nonlocality" (Nature link to abstract) have rewritten their equation 1 in terms of equation 2 and 3?

enter image description here

One Answer

First, in order to express $|H'rangle$, $|V'rangle$, $|Rrangle$ and $|Lrangle$ in terms of $|Hrangle$ and $|Vrangle$, add and subtract the pair of equations $(2)$ and add and subtract the pair $(3)$, to get

$$ |H'rangle + |V'rangle = sqrt2|Hrangle |H'rangle - |V'rangle = sqrt2|Vrangle |Rrangle + |Lrangle = sqrt2|Hrangle |Rrangle - |Lrangle = isqrt2|Vrangle $$

which means that

$$ |Hrangle = frac{1}{sqrt{2}}left(|H'rangle + |V'rangleright) = frac{1}{sqrt{2}}left(|Rrangle + |Lrangleright) |Vrangle = frac{1}{sqrt{2}}left(|H'rangle - |V'rangleright) = frac{1}{isqrt{2}}left(|Rrangle - |Lrangleright). $$

Substituting the last equations into $(1)$ according to the choices of polarization in text, we obtain

$$ begin{align} |Psirangle &= frac{|Hrangle|Hrangle|Hrangle + |Vrangle|Vrangle|Vrangle}{sqrt{2}} & = frac{(|Rrangle + |Lrangle)(|Rrangle + |Lrangle)(|H'rangle + |V'rangle)-(|Rrangle - |Lrangle)(|Rrangle - |Lrangle)(|H'rangle - |V'rangle)}{4}. end{align} $$

Notice that the only terms that do not cancel are those with odd number of kets in ${|Lrangle,|V'rangle}$, i.e.

$$ |Psirangle = frac{1}{2}left(|Lrangle|Rrangle|H'rangle + |Rrangle|Lrangle|H'rangle + |Rrangle|Rrangle|V'rangle + |Lrangle|Lrangle|V'rangleright) $$

in agreement with $(4)$.

Answered by Adam Zalcman on July 21, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP