Entanglement Swapping Circuit

There is a mistake in design of the first circuit. Both $X$ and $Z$ gate work when value 1 is in classical register.

Gate $X$ should work in case qubit $q_2$ is in state $|1rangle$. Similarly $Z$ acts when $q_1$ in state $|1rangle$. Also you have to deal with state when both $X$ and $Z$ have to act. In your case you conditioned both $X$ and $Z$ on c==1. It means that both gates act in case $q_1$ is in state $|1rangle$. Another mistake come from measuring qubits $q_1$ and $q_2$ in the first circuit while not to measure them in the second one (in this case they are alway zero).

Please see here QASM commented code producing results you desired:

OPENQASM 2.0;
include "qelib1.inc";

qreg q[4];
creg c[5];

//teleport
h q[0];
h q[2];
cx q[0],q[1];
cx q[2],q[3];
cx q[1],q[2];
h q[1];

//measuring q1 and q2
//for controlled gates

measure q[2] -> c[0];
measure q[1] -> c[1];

//set q1 and q2 to |0> to
//emulate they are not measured
reset q[1];
reset q[2];

//controlled gates
  //q1 = |0>, q2 =|1>
if (c==1) x q[3];
  //q1 = |1>, q2 =|0>
if (c==2) z q[3];
  //q1 = |1>, q2 =|1>
if (c==3) x q[3];
if (c==3) z q[3];

//measure qubits
measure q[3] -> c[3];
measure q[0] -> c[0];
measure q[1] -> c[1];
measure q[2] -> c[2];