Physics Asked on February 12, 2021
By Kinetic Theory of Gas,
$K.E = frac32 RT$ (i.e it is independent of mass of the gas)
Its proof is as follows:
We know , $P = frac13 Dcdot v^2$ (where $D$ is mass density and $v$ is average of the squared velocity of molecules)
Multiply both sides by $V$(Volume)
$$
PV = frac13 Mv^2
$$
Multiply and divide by $2$ in the rhs of the equation
$$
PV= frac23 × frac12 Mv²
$$
$$
PV= frac23 × K.E ~~~~~~~~[1]
$$
$$
RT= frac23 × K.E
$$
$$
K.E = frac32 RT
$$
But in [$1$] we used that $frac12 Mv^2= K.E$ (i.e $K.E$ as a function of Mass).
In the end we got $K.E= frac32 RT$ (i.e $K.E$ is independent of Mass)
Please explain how $K.E$ of gases is independent of Mass
Because relative change in the number of microstates with energy does not depend on mass.
That is what thermal equilibrium is: when $frac{1}{Omega} frac{{rm d}Omega}{{rm d}E}$ is equal for two systems. Then their temperatures are the same.
So the number of microstates $Omega$ att a certain energy depends on mass, but not the logarithmic derivative with respect to energy.
Answered by Pieter on February 12, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP