Why has $evB$ been equated to $mv^2/R$ here?

Question

When $24.8 keV$ x-rays strike a material, the photoelectrons emitted from K shell are observed to move in a circle of radius $23mm$ in a magnetic field of 2 × $10^{-2}$. The binding energy of K shell electrons
Now the solution is something like this

My doubt is why have they equated $evB$ to $Mv^2/R$??

BioPhysicist · Accepted Answer

The electrons are undergoing uniform circular motion due to the magnetic force. Therefore, the centripetal force component is equal to the magnetic force. I'll leave the calculation (if you can call it that?) to you.

Correct answer by BioPhysicist on January 23, 2021

Charan T · Answer

$F=BqV$ is the force experienced by a moving charge in a magnetic field.so, as charge moves in circular path we equate this to the required centripetal force(=$frac{mv^2}{r}$)now you can proceed with the solution

Answered by Charan T on January 23, 2021

Why has $evB$ been equated to $mv^2/R$ here?

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