Physics Asked by Bizniouf on September 1, 2021
I am in trouble with polarization and entanglement.
Let’s consider three cases :
Case 1) : Statistical mixture of $|Hrangle$ and $|Vrangle$ polarized photons
Case 2) : Photons in a superposition state $1/sqrt{2}(|Hrangle+|Vrangle)$
Case 3) : Photons which are entangled with twin ones in $1/sqrt{2}(|H,Hrangle+|V,Vrangle)$ state
Which experiments can be conducted to differentiate the case
statistical mixture from the case
superposition state ?
Which experiments can be conducted to differentiate the case
statistical mixture from the case
entangled photons in superposition state ?
Using a $45^circ$ polarizer I think you can differentiate case 1/case 2 but not case 1/case 3
I don’t know how to differentiate case 1/case 3 except maybe using quantic tomography and Wigner function. Is it true ? Is there any other simpler way ?
Thanks a lot for your answer and sorry for this maybe dummy question…
If a state in a finite dimensional space is pure, it will be an eigenstate of some hermitian operator. Thus measuring this operator on your test state will result in this outcome 100% of the time.
You correctly concluded that in your Case2 the operation is polarization at $45^circ$. In your case 3 you have a composite state so it lives in the space of states with polarization $L=1$ and $L=0$. It looks like your state (because it is symmetric under exchange of the first and second particle) is probably in the $L=1$ subspace only, and I would think that $vert psiranglelangle psivert$ can be expressed of quadrupole moments, and would be an eigenstate of some linear combination of these quadrupole moments. How to measure such moments for polarization I do not know.
Note that in a finite dimensional space any state $vertpsirangle$ is pure, whether it is a single-particle or a composite state. Actually doing the measurement is something else but there is literature on this:
Band and Park have a series of paper on this general topic, most of which are precursor to the more general topic of quantum tomography for state reconstruction. For instance, in the case of a spin-$1/2$ system, the density matrix can be completely reconstructed by measuring $sigma_x,sigma_y$ and $sigma_z$, and then it's a matter of just testing if this density matrix describes a pure or a mixed state.
Answered by ZeroTheHero on September 1, 2021
As you've pointed out, a polarizer (or, more usefully, a polarizing beam splitter) at 45° orientation will separate cases 1 and 2.
Case 3 (entangled photons) cannot be distinguished from case 1 (statistical mixture) using observables from only the first photon. This is because the reduced density matrix for case 3 reads begin{align} rho_A & = mathrm{Tr}_Bbig[|Psi⟩⟨Psi|big] & = frac12 mathrm{Tr}_Bbigg[{rm (|HH⟩+|VV⟩)(⟨HH|+⟨VV|)}bigg] & = frac12 mathrm{Tr}_Bbigg[{rm |HH⟩⟨HH|+|HH⟩⟨VV|+|VV⟩⟨HH|+|VV⟩⟨VV|}bigg] & = frac12 bigg[{rm |H⟩⟨H|+|V⟩⟨V|}bigg] , end{align} i.e., the maximally-mixed state that describes a statistical mixture. Since the reduced density matrix $rho_A$ fully determines the outcome of all local experiments, no such experiment can distinguish between the two cases.
That said, case 3 can be distinguished easily from case 1 by putting an H/V polarizing beam splitter on both of the twin systems, and correlating the two outputs.
(Of course, that doesn't guarantee you that the system is in an entangled state, as that protocol cannot distinguish case 3 from a statistical mixture $rho = frac12 big[{rm |HH⟩⟨HH|+|VV⟩⟨VV|}big]$ with classical correlations; to benchmark the entanglement you would need to show a Bell-inequality violation, or a full quantum state tomography if you're feeling fancy.)
Answered by Emilio Pisanty on September 1, 2021
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