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Where does one more '$rm m$' come from in the units?

Physics Asked on May 16, 2021

$$nabla times A = B$$

$A$ is vector magnetic potential, $mathrm{Wb/m}$

$B$ is magnetic field intensity, $mathrm{Wb/m^2}$

Where does one more m come from for $B$? Is that from the gradient operator so it is in meter or something?

2 Answers

The del operator is

$$nabla = [frac{d}{dx},frac{d}{dy},frac{d}{dz}] $$

and ends up taking derivatives of A with respect to x,y,z axis, which are displacements measured in meters.

Since a derivative is a rate of change, you are finding the change in A(Wb/m) per meter, hence $$frac{Wb/m}{m}=Wb/m^2$$.

Answered by DKNguyen on May 16, 2021

As you suggested the del operator provides the additional “per/meter”. The del is the rate of change with respect to position. So just like taking a derivative with respect to time divides the units by time so also taking a derivative with respect to position divides the units by distance.

Answered by Dale on May 16, 2021

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