Physics Asked by user284935 on February 2, 2021
I found in my textbook that
Oscillation of light wave mainly represents the periodic change of electric field $ vec E$ as contribution of $vec E$ is the most significant here which creates optical sensation to our eyes.. The direction of the electric vector can be in any direction among all directions on a plane perpendicular to the direction of wave propagation named as electromagnetic wave. But at any given point in time, there will be only one resultant magnetic field.
But according to the figure, I see two fields symmetric here. And ‘Ampere’s Law’ roughly states that ‘a changing electric field creates a magnetic field’. Then how can in a particular moment, magnetic field be in any one arbitrary direction?
In SI units, the E-field amplitude is $c=3times 10^8$ m/s larger than the B-field amplitude. But this is just a consequence of choice of units. It is perfectly possible to adopt a system of units where $c=1$ and $E=B$. Then, the diagram of the fields at a snapshot in time would be as shown in your question, with similar numbers along the axes perpendicular to the wave propagation direction.
Where there is an asymmetry is with the effect that the fields have on charges.
The electric component of the force is $qvec{E}$ and would usually be much larger than the magnetic component $qvec{v}times vec{B}$ (in either set of units) unless the charge velocity $v$ is an appreciable fraction of the speed of light.
Why this asymmetry? Well, that is how the magnetic field $vec{B}$ is defined. Both $vec{E}$ and $vec{B}$ are not relativistically invariant and are different aspects of one "electromagnetic field".
In terms of direction of the fields there is no asymmetry there. The E- and B-fields are both in the plane perpendicular to the wave propagation direction and mutually perpendicular. We may choose to define the direction of one field and then that completely determines the direction of the other.
Answered by ProfRob on February 2, 2021
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