Physics Asked on September 17, 2020
When reading Mechanism for ordinary-sterile neutrino mixing it is stated in the abstract that:
"(…)sterile neutrinos can occur only if Dirac and Majorana mass terms exist which are both small and comparable."
What is the meaning of comparable in this context? Does it means both mass terms must be on a similar scale (energy wise)?
Later in the article the conditions for them to be comparable are given, but it still doesn’t say what comparable truly means.
Your reference is just fine and clear, and refers you to [2] and [20] if you wish to know more. It discusses its mass matrix (1) mixing active and sterile species.
If $m_D=0$, or $m_M=0$, there is no mixing. If $m_Dll m_M$ as in the celebrated see-saw scenario, the masses of the eigenstates are huge ($m_M$) and small ($m_D^2/m_M$), respectively, but then the mixing is insignificant, $O(m_D/m_M)$; this is what the author is reminding your to exclude.
So in order to have nontrivial sterile neutrinos that matter (~are observable, indirectly: second class oscillations), you need comparable mass matrix parameters $m_D$ and $m_M$, i.e. they are comparable numbers, like 1 and 3.7 times a common mass scale. That mass scale must, of course, be small, since we are talking about neutrino masses, and we know active neutrino masses are small.
Correct answer by Cosmas Zachos on September 17, 2020
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