Physics Asked on July 30, 2021
What is the meaning of non-resonant production in the following context:
They assumed a negligible primordial lepton number,or asymmetry, so
the neutrinos are produced non-resonantly. [1]
I thought that this meant that the reaction would not resonate, meaning that it would only "go one way". But I don’t believe this is correct.
I have also read on the Wikipedia page: Resonance, that it "is the peak located around a certain energy found in differential cross sections of scattering experiments." But it also doesn’t seem to be the same type of resonance, or am I wrong?
I have also found the following slides but I don’t understand their explanation.
[1] – K. Abazajian, G. M. Fuller and M. Patel, "Sterile Neutrino Hot, Warm, and Cold Dark Matter", Phys. Rev. D 64 (2001) 023501, arXiv:astro-ph/0101524.
The resonance they are talking about is very much the same kind of resonance that you quote from Wikipedia. If you look at equation (6.6) of reference [1] that you gave, you see that the evolution of the sterile neutrino phase space density $f_s$ is governed by this big fraction on the right hand side. In the denominator you find the potentials $V_L$ and $V_T$ both with a negative sign. If large enough, they might compensate the other terms in the denominator to a very high degree. This would make the denominator very small and thus the right hand side of equation (6.6), which one can think of as the sterile neutrino production rate, very big. This is what is meant by resonance. As it turns out, for a resonance to occur one needs the potential $V_L$, which in return requires a primordial lepton asymmetry. If you don't have such an asymmetry, there will be no resonance and the sterile neutrino production will take place only non-resonantly, which is what the authors of [1] say.
Answered by Formelverleger on July 30, 2021
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