Physics Asked on May 24, 2021
What is the meaning of the term "natural width" in particle physics?
From http://nordberg.web.cern.ch/PAPERS/JINST08.pdf, page 2:
… there is a range of production and decay mechanisms, depending on the mass of the Higgs boson, $H$. At low masses ($m_H < 2m_Z$), the natural width would only be a few MeV, and so the observed width would be defined by the instrumental resolution.
I think they refer to the decay width of the Higgs boson. By "natural", I think, they mean the ideal width that is predicted by the theory and that would be observed in the plots if everything was measured with an infinite precision. In reality the detectors are not perfect and measure the energy/momentum of particles with some error, which leades to smearing of the peak.
Answered by lv995 on May 24, 2021
To add onto what has already been said: the "theory" width tells you how far away the mass of a particle can be from its nominal mass. That is an energy spread. And that spread is related to the lifetime. Due to the uncertainty principle, a short lifetime requires a large energy range (or mass range or natural/theory width, whichever term you prefer). And vice versa.
Answered by xenon on May 24, 2021
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