TransWikia.com

What is $dfrac{partial x}{partial t}$ in a progressive wave?

Physics Asked by Neerav Singla on May 4, 2021

I actually divided the velocity of a particle in a progressive wave $dfrac{partial y}{partial t}$ to $dfrac{partial y}{partial x}$ and got $dfrac{partial x}{partial t}$. Which is equal to $dfrac{-omega}{k}$ . Mathematically it is equal to $-V$. But I am not getting its qualitative meaning.
enter image description here

I divided the two highlighted equations
Also, can I even divide two derivatives which have different constants$?$

One Answer

In the general sense, it is wrong to think about the derivative (partial or total) $frac{partial f(x)}{partial x}$ as a fraction. For a finite difference, it is fine, but since the derivative is the infinitesimal limit of a fraction, it is not necessarily well-defined how to treat numerator and denominator separately.

Rather, for full derivatives you might use the chain rule $frac{d f}{d x} = frac{d f}{d t} frac{dt}{dx} $, which, however, is more complicated in the case of partial derivatives. The most straightforward way of finding $frac{partial x}{partial t}$ might be to invert $y(x)$ to find $x(y)$ and then taking the time derivative directly.

Note that in physics we often perform substitution of variables in integrals by pretending the fraction is well-defined. One must be very careful, since this only works under certain circumstances.

Correct answer by Codename 47 on May 4, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP