Understanding the Sommerfeld radiation condition?

So what is the true meaning of the Sommerfeld radiation condition, does it imply a wave decays to zero, or a radiating wave decays to a plane wave, or something else.

From the quote by Sommerfeld below, it seems to me that "scatter to infinity" can be taken as a wave decaying to zero.

From Wikipedia Sommerfeld Radiation,

Arnold Sommerfeld defined the condition of radiation for a scalar field satisfying the Helmholtz equation as

"the sources must be sources, not sinks of energy. The energy which is radiated from the sources must scatter to infinity; no energy may be radiated from infinity into ... the field."

Mathematically, consider the inhomogeneous Helmholtz equation${displaystyle (nabla ^{2}+k^{2})u=-f{mbox{ in }}mathbb {R} ^{n}}$where ${displaystyle n=2,3}$ is the dimension of the space, ${displaystyle f}$ is a given function with compact support representing a bounded source of energy, and ${displaystyle k>0}$ is a constant, called the wavenumber.

A solution ${displaystyle u}$  to this equation is called radiating if it satisfies theSommerfeld radiation condition$${displaystyle lim _{|x|to infty }|x|^{frac {n-1}{2}}left({frac {partial }{partial |x|}}-ikright)u(x)=0}{displaystyle {hat {x}}={frac {x}{|x|}}}$$(above, ${displaystyle i}$ is the imaginary unit and ${displaystyle |cdot |}$ is the Euclidean norm). Here, it is assumed that the time-harmonic field is ${displaystyle e^{-iomega t}u.}$ If the time-harmonic field is instead ${displaystyle e^{iomega t}u,}$ one should replace ${displaystyle -i}$ with ${displaystyle +i}$ in the Sommerfeld radiation condition.

For your second point:

What is the LHS of the equation saying? It doesn't very intuitive what with the multiplication of u by ik?

From Eighty Years of Sommerfeld's Radiation Condition - CiteSeerX (There is a PDF associated with this file, which, for some reason I cannot link directly to). My apologies for this, but the PDF does provide a possible rational for the formulation of the equation, i. e. in order to remove unwanted unphysical solutions.

One of the difficulties with formulating a wave propagation problem in this way is that the solution may not be unique. Besides the expected outgoing waves which result when the incident wave is scattered by the object, the mathematical solution also provides incoming waves which originate at infinity and move towards the object. These incoming waves are physically meaningless and must be rejected by some criterion built into the mathematical formulation of the problem. Sommerfeld was the first to state a mathematically precise and easily applicable condition which, when added to exterior boundary value problems for the Helmholtz equa- tion, ensures a unique solution. This condition is applied at infinity and for three- dimensional problems requires that the solution u satisfy $Y= Vx’ + y= + 22, i=CT$, uniformly with respect to all directions in which the limit is approached.

In the (very likely) case that there are subtle aspects to this that are well beyond me, I would ask that you google the above reference and download the PDF.

The Sommerfeld radiation condition is used to solve uniquely the Helmholtz equation. For example, consider the problem of radiation due to a point source ${displaystyle x_{0}}$ in three dimensions, so the function ${displaystyle f}$ in the Helmholtz equation is ${displaystyle f(x)=delta (x-x_{0}),}$ where ${displaystyle delta }$ is the Dirac delta function. This problem has an infinite number of solutions, for example, any function of the form

${displaystyle u=cu_{+}+(1-c)u_{-},}$w here ${displaystyle c}$ is a constant, and ${displaystyle u_{pm }(x)={frac {e^{pm ik|x-x_{0}|}}{4pi |x-x_{0}|}}.}$

Of all these solutions, only ${displaystyle u_{+}}$ satisfies the Sommerfeld radiation condition and corresponds to a field radiating from ${displaystyle x_{0}.}$. The other solutions are unphysical. For example, ${displaystyle u_{-}}$ can be interpreted as energy coming from infinity and sinking at ${displaystyle x_{0}.}$