Shockley diode equation - temperature influence

when looking at Shockleys ideal diode equation I wonder what "meaning" the temperature has in there?

If I assume $$I(T) = I_0 left(exp left( frac{U}{k_BT/q}right)-1 right)$$

and vary the temperature (250K,300K,350K -> blue, yellow,red) I’ll see exactly the opposite trend of what I would’ve expected. I expect that at higher temperature the diode will start to conduct at lower voltages, but the opposite is given by Shockleys equation. What am I missing here?

thanks…