Physics Asked by Akshit on December 24, 2020
Consider two mirrors, which intersect at an angle. Let us talk about geometric optics. If we draw a light ray intersecting the mirrors at their point of intersection, how will it reflect?
What will be the normal at that point?
It is overdefined geometry. By most optics ray tracing simulation software it will be treated as absorption.
The intersection point belongs to two interfaces at once. Praxis differs
Depending on your application you should stick either to advance your model with a curved edge or assume this ray is absorbed. In a ray tracing simulation this one ray will not affect simulated irradiance. However you may take a closer look if performing a stray light analysis.
Correct answer by Stefan Bischof on December 24, 2020
It is not well defined, but that is not a problem because no rays hit the point precisely. If you are a little on one side or the other you know what happens. It is like choosing a uniform random number on $[0,1]$. The chance of each number is zero, which is what it takes to hit the corner exactly.
Answered by Ross Millikan on December 24, 2020
There is no physical beam that is infinitely thin.
In fact in the quantum physical world each free space light beam extends infinitely in space. It falls off rapidly, but there is a probability finding the photon at arbitrarily far distance.
So, since each beam has a certain thickness, even in case we assume the angle is infinitely sharp the behavior is well defined. In the geometrical approximation, by just separate reflection of the two beam parts hitting the two mirrors.
Answered by Andreas H. on December 24, 2020
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