Physics Asked by lralvare on May 3, 2021
first time poster in this site.
I am trying to create a small program to make a graph of the Carnot cycle.
For isothermals I am simply trying to look for points where P*V would give the same Temperature so that I can display an isothermal curve.
However, I am having absolutely no luck with trying to plot an adiabatic curve.
I know I want a steeper curve, but thats about it. Is there some sort of simpler way to draw out an adiabatic curve? Can I set any variable constant and try to draw the curve like an isotherm?
Any information is appreciated.
//ISOTHERMS
//i = x axis; j = y axis;
// for values 1 - 350
// plot y values from isothermal equation -- P*V = constant T
// j = k/i
int k1 = 5000;
//int k1 = 1500;
//int k1 = 15000;
//int k2 = 20000;
int k2 = 15000;
//int k2 = 30000;
g.setColor(Color.red);
for( int i = 1; i < 350; i++)
{
int j1 = k1/i;
int j2 = k2/i;
//if(j1 < 350)
g.drawLine(i+50, j1+50, i+50, j1+50);
//if(j2 < 350)
g.drawLine(i+50, j2+50, i+50, j2+50);
}
//ADIABATS
//P*V^gamma = constant T
double gamma = 1.67;
for( int m = 1; m < 500; m++)
{
// int h1 = (int) (1400000/(Math.pow(m,1.97)));
int h1 = (int) (1000000/(Math.pow(m,2)));
//int h2 = (int) (3500000/(Math.pow(m,1.97)));
int h2 = (int) (2400000/(Math.pow(m,2)));
//if(j1 < 350)
g.setColor(Color.blue);
g.drawLine(m+50, h1+50, m+50, h1+50);
//if(j2 < 350)
g.drawLine(m+50, h2+50, m+50, h2+50);
}
$PV^{gamma}=Const$, where $gamma = C_p/C_v$
Answered by Chet Miller on May 3, 2021
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