Physics Asked by Achnos on June 25, 2021
In QFT we define the scattering matrix from the scattering amplitude as
$$
S_{fi} = limlimits_{trightarrow infty}limlimits_{t_0rightarrow -infty }leftlangle fleft|U(t,t_0)right|i rightrangle = delta_{fi} +(-i)(2pi)^4delta^4(p^mu_f-p^mu_i)underbrace{mathcal{M}_{fi}}_{text{Scatt. Amp.}} + dots ; ,
$$
such that once we wish to obtain the probability of a scattering event, we need to evaluate $|M_{fi}|^2$. In the case where we want to obtain the full probability, we should sum over all of these individual amplitudes.
I understand $S_{fi}$ as the unitary transformation matrix that relates the initial and final states, while $M_{fi}$ is a probability density of a certain event occuring. What is the physical interpretation of $S_{fi}$. Is it also a probability density?
In Sakurai, Modern Quantum Mechanics, a so-called transition matrix $T_{fi}$ is defined from $langle f| V(r) | irangle$, how is this related, why is it useful, and how does one interpret it?
The S-matrix is the amplitude to transition from an initial state to some final state, so it evolves the initial state to the final state, $$ S_{fi}=langle f|U(infty, -infty)|irangle, $$ and since the evolution operator is unitary, the matrix (to all final states) is unitary, that is the initial state must scatter to some final state, including itself, for sure: it can't just disappear! That is, the transition probabilities to all final states sum to one, $$ S^dagger S= sum_f |langle f|U|irangle|^2 =1. $$
For a free theory, the final state is the undisturbed initial one, so the S-matrix is the identity: nothing happened. But if there is an interaction term, a potential, there is an amplitude to scatter to a different state, an off-diagonal state, and that amplitude increases with the "potential" or "interaction hamiltonian", the Dyson series of which yields an approximation to $U(t,t_0)$. Actually, in the interaction representation used most often, to $U_I(t,t_0)= e^{iH_0t/hbar} U(t,t_0) e^{-iH_0t_0/hbar}$.
In plain NR QM, the eigenstates of the free hamiltonian are plane waves, so the amplitude to transition from a plane wave to a distinctly different plane wave f is $$ T_{fi}=langle f|V|irangle , $$ so the probability of this distinct transition is $|langle f|V|irangle |^2$. That is, it is the nontrivial piece of the S-matrix, up to a convenience normalization in plane wave scattering, $$ S-1!! 1 = -2pi i T. $$ The unitarity of S then presents as $$ T^dagger -T - 2ipi T^dagger T =0 . $$ It is useful because in scattering experiments we normally ignore the forward stream of projectiles (which went through the target), and attend to the scattered products, which tell us something about the potential which scattered them. (Recall the Geige-Marsden experiment.)
Correct answer by Cosmas Zachos on June 25, 2021
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