Peaks in Co-60 gamma spectrum

You have already identified the peak at about 195 keV as backscatter peak.

Apparently, you have used a NaI(Tl) detector. Photoelectric absorption by iodine of NaI results in a characteristic x-ray with 28 keV. If this x-ray exits the detector crystal, it results in a secondary peak 28 keV below the corresponding photopeak.

Since 195 keV minus 28 keV is 167 keV, we may conclude that your peak at 167 keV is the iodine x-ray escape peak corresponding to the backscatter peak.

You cannot see the iodine x-ray escape peak corresponding to the photopeak at 1.17323 MeV because it is hidden in the spread of the photopeak.