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OPE leading twist = collinear factorisation?

Physics Asked by CAF on March 24, 2021

The operator product expansion systematically expands QFT interactions in terms of a sum of local operators.

Is the leading twist of this expansion identifiable with collinear factorisation and, if so, how is this reconciled with the fact that the input Parton densities are quantum field theoretically defined in terms of non-local operators?

One Answer

I'm not well-educated on this topic but maybe this helps you anyway:

In Weinberg's vol. 2 there is a section about deep inelastic scattering, in which it is shown that the correspondence between the local operator expectation values of the OPE and the PDF holds only for the moments (i.e. Mellin transform) of the PDF (but without using operator definitions of the PDFs). So you can not just identify the PDFs with the local operators of the OPE.

You might want to take a look at this paper which defines the operator representations of PDFs. It has a section on how to relate these to local twist-two operators. But it is also noted that the relation is approximate.

Answered by drfk on March 24, 2021

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