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Non-hamiltonian systems which evolve into hamiltonian by change of coordinates

Physics Asked by Nope on March 16, 2021

I am very new to the subject, so please forgive my very naïf question. I learned that there are some non-hamiltonian systems which can become hamiltonian, just by a change of coordinates. I was given SIR (Susceptible – Infected – Removed) model as an example:
begin{cases}
frac{dS}{dt} = – alpha SI
frac{dI}{dt} = alpha SI – beta I
frac{dR}{dt} = beta I
end{cases}

with $alpha$ and $beta$ being real parameters.

This is clearly non-hamiltonian because it is associated with a vector field which has non zero divergence. However, by choosing $x= log(S)$ and $y= log(I)$, where $S$ and $I$ are the susceptible and infected respectively, the system becomes hamiltonian.

What I found really strange about this result is that I’m used at seeing quantities being preserved by a change of coordinates, while here the property of the system being hamiltonian clearly isn’t intrisinc: is there something deeply conceptual that I’m missing about hamiltonian mechanics?

One Answer

  1. Note that the divergence ${rm div}_{rho}X=rho^{-1}partial_i(rho X^i)$ of a vector field $X=X^ipartial_i$ in general depends on a density $rho$, cf. above comment by user mlk. The possibility of a non-trivial $rho$ makes it more difficult to identify which 1st-order systems are potentially Hamiltonian and which are not.

  2. A 3D phase space can never have a non-degenerate symplectic structure, but if we ignore the last coordinate $R(t)=betaint^t!dt^{prime} I(t^{prime})$, then we have a 2D phase space, which always has a (local) Hamiltonian formulation, cf. this Phys.SE post.

  3. Concretely, the SIR-model $$begin{align} dot{S}~=~& - alpha SI~=~{S,H}, cr dot{I}~=~& alpha SI - beta I~=~{I,H},cr dot{R}~=~& beta I~=~{R,H},end{align} tag{1}$$ has non-canonical, degenerate Poisson structure $$begin{align} {S,I}~=~&SI, cr {I,R}~=~&frac{beta}{alpha}I, cr {S,R}~=~&0,end{align} tag{2} $$ and Hamiltonian $$ H~=~beta ln S -alpha (S+I) .tag{3} $$

  4. If we follow OP's suggestion to change coordinates $$begin{align} s~:=~&ln S, cr i~:=~&ln I , cr r~:=~&R, end{align}tag{1'}$$ then the fundamental Poisson brackets (2) become constant $$ begin{align} {s,i}~=~&1, cr {i,r}~=~&frac{beta}{alpha}, cr {s,r}~=~&0, end{align}tag{2'} $$ and it becomes obvious that the Jacobi identity is satisfied as it should. The Hamiltonian reads $$ H~=~s -alpha (e^s+e^i) tag{3'} $$ in the new coordinates.

Correct answer by Qmechanic on March 16, 2021

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