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NMR spectroscopy

Physics Asked on December 18, 2020

I was wondering how many times larger is the magnetic moment of an electron compared to a proton? How come the electrons magnetic moment play no role in NMR and MRI? Edit Electron Spin Spectroscopy exists

https://www.researchgate.net/figure/Figure-A1-Precession-of-a-magnetic-dipole-in-a-magnetic-field-The-external-magnetic_fig21_48375299

I see how the average magnetic moment is pointing upwards with time but once an RF field has excited the spin it would look like this:

https://www.slideserve.com/barrett-mayer/section4-an-assembly-of-non-interacting-spins

which would still add up to being vertical or zero.
Unless the special case

Is this what they mean by the RF pulse only working on interacting spins not non interacting spins?

One Answer

Mass of the proton is nearly 1837 times heavies than the mass of electron and hence the electronic magnetic moment is greater that the nuclear magnetic moment by this ratio.

It is not true, electrons play no role in NMR, conversely they are paramount because the main information we obtain in a NMR spectrum is the chemical shift that comes directly for the effects of the electron density on the nucleus.

The magnetic field the nucleus experiences differs slightly from the applied field, $B_0$ , because the magnetic field at the nucleus is shielded by the electron density surrounding the nucleus. This shielding is due to precession of electrons under the influence of the applied magnetic field. This precession generates an additional magnetic field that usually opposes the externally applied magnetic field. The local magnetic field strength at the nucleus is given by:

$B = (1 - sigma) · B_0$

As the electron density around the nucleus increases, the effective field decreases, leading to lower resonance frequencies. Since the resonance frequency is due to the chemical environment of the nuclear spin, the observed frequency is referred to as a chemical shift.

Answered by gioretikto on December 18, 2020

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