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Newtonian deflection of light and energy conservation

Physics Asked by MiKiDe on March 16, 2021

I was looking at some calculations of the deflection of light by the sun.
However, there is something that I cannot understand. They usually express a relation $$r = dfrac{p}{1+ecos(theta)} qquad (star) $$ as if it were massive, knowing that nothing in this expression depends on the mass (but it depends on the massive energy $epsilon = E/m$).

Here’s the "energy" conservation for a massless particle (it has the dimension of energy over a mass) :
$$
epsilon = frac 1 2 c^2 – frac kappa r
$$

with $kappa = GM_s$, where $M_s$ denotes the sun’s mass.

I believe that in this paper1, they assume that $(star)$ holds:

A light ray, from a distant star, under the Sun’s gravitational force field describes the usual central force hyperbolic orbit.

So here’s my problem: since $c$ is a constant, how can $epsilon$ be a constant knowing that $r$ is not?


Warning: I choose to right as $e$ the eccentricity and $epsilon$ the quantity conserved through the movement. However, in the paper I linked above, they denote $epsilon$ the eccentricity!


1 D. S.L. Soares, "Newtonian gravitational deflection of light revisited", arXiv:physics/0508030.

2 Answers

In these calculations, the light is modeled as an ordinary particle whose speed happens to be $c$ either at infinity or at the point of closest approach. The speed isn't (and can't be) constant on the whole orbit. The paper that you linked sets the speed to $c$ at closest approach (see the text after equations 5 and 7).

There's really no adequate Newtonian theory of light, so the concept of computing the Newtonian gravitational deflection of light doesn't make a lot of sense. The alternatives to treating light as an ordinary particle are treating it as a particle moving at infinite speed (which would lead to a prediction of no deflection) or as a wave in a luminiferous aether (in which case I suppose the prediction would depend on how gravity affects the aether).

Correct answer by benrg on March 16, 2021

As I vaguely remember, Newtonian gravity does not have any affect on light. Einstein's General Relativity was the first prediction about gravity bending light, and this was confirmed a few years later by seeing the effect in a telescope during a full solar eclipse.

Answered by Buzz on March 16, 2021

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